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4 years ago

Find the equation of the vertical passing through the point (3,7), (30,-11), and (0, -1)

Mathematics

1 answer:

mrs_skeptik [129]4 years ago

3 0

Answer:

y = 7.

y = -11.

y = -1.

Step-by-step explanation:

All the verticals on the coordinate plane are either y-axis or parallel to the y-axis.

And the equations of all the vertical straight lines on the coordinate plane is given by y = c ........... (1), where c is any real constant.

Now, putting c = 0 we will get the equation of y-axis i.e. y = 0.

Therefore, y = 7 is the equation of a vertical passing through (3,7) points.

The equation of the vertical passing through (30,-11) is y = -11.

And the equation of the vertical passing through (0,-1) is y = -1. (Answer)

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8/2=6/n+4 Solve for n

Reptile [31]

Answer:

No solution (because the n's cancel out!)

Step-by-step explanation:

Let's solve your equation step-by-step.

Multiply all terms by n and cancel:

=6+4n

4n=4n+6(Simplify both sides of the equation)

4n−4n=4n+6−4n(Subtract 4n from both sides)

0=6

Answer:

No solutions.

8 0

4 years ago

When Cameron moved into a new house, he planted two trees in his backyard. At the time of planting, Tree A was 24 inches tall an

Darina [25.2K]

Answer:

time interval when Tree A is taller than Tree B is;

t > 5 years

Step-by-step explanation:

Tree A;

Initial height = 24 inches

Increase in height per year = 6 inches per year

Thus, for t years after being planted, height is;

A = 6t + 24

Tree B;

Initial height = 39 inches

Increase in height per year = 3 inches per year

Thus, for t years after being planted, height is;

B = 3t + 39

For tree A to be taller than tree B, then it means thay;

A > B

Thus;

6t + 24 > 3t + 39

Subtract 3t from both sides to get;

6t - 3t + 24 > 39

3t + 24 > 39

3t > 39 - 24

3t > 15

Divide both sides by 3 to get;

t > 5

Thus, time interval when Tree A is taller than Tree B is; t > 5

4 0

3 years ago

What is 25 and 5/8-12

Burka [1]

92/3, i calculated 25+5/8 over 12
and if u divide 92/3 u get 30.66

6 0

3 years ago

(3x2 - 4x +8)+(-x2 – 2x – 8)

diamong [38]

Hey there,

The question given is as follows:

(3x² - 4x + 8) + (-x² - 2x - 8)

When we add polynomials we add like terms (e.x. we add 3x² with -x²) and combine the two to make one polynomial. When we add the two polynomials given above:

2x² - 6x + 0

So our answer to the problem would be 2x² - 6x.

Hope I helped,

Amna

3 0

4 years ago

Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr

Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

$L=L_1+L_2$

$L_1=\sqrt{80^2+x^2}$

$L_2=\sqrt{60^2+(100-x)^2}$

$L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}$

differentiate w.r.t x we get

$\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

Put $\frac{\mathrm{d} L}{\mathrm{d} x}=0$ to get minimum value

$\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

squaring

$x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)$

Rearranging

$28x^2-1800x+640000=0$

$x=\frac{400}{7}$

thus $L_1=98.312 ft$

$L_2=73.73 ft$

$L=172.04 ft$

7 0

3 years ago