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LuckyWell [14K]
3 years ago
15

Help ASAP please! Really am struggling with this topic

Mathematics
2 answers:
Travka [436]3 years ago
7 0
I dont have an answer buy i need to answer a question so i can ask my question sry
SpyIntel [72]3 years ago
7 0

Answer:

Slope for the first would be 3 and the y intercept is 1. For the second the slope is -4 and the y intercept is 140.

Step-by-step explanation:

For the first one the difference between the first second point is up 6 and over 2 so 6/2= 3 or slope and the y intercept is just where the line intersects the y axis.

For the second question the difference between the points is down 20 units and over 5 so -20/5= slope of -4, and the line intersects the y axis at 140 so that is the y intercept.

If the x value is zero then the y value is the y intercept.

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fiasKO [112]

Answer:

number of commercial=4

number of movies=4

4 times 20=80

80 times 4= 320

320+80=400

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
3 1/3 /20 what is the quotient
AleksAgata [21]

Answer:

1/6

Step-by-step explanation:

(3 1/3)/20=(10/3)×(1/20)=10/60=1/6

3 0
3 years ago
What is the equation of the line in slope-intercept form?
GREYUIT [131]
Y=5/2x+5 because the slope is 5/2 and the y-intercept is 5
6 0
3 years ago
What is the lcm of 6 and 8
Dafna1 [17]

Answer:

Explanation:

Method 1

First, list the multiples of both numbers:

undefined

To find the lowest common multiple (LCM) of 6 and 8, first express the numbers as a product of its prime factors.

\begin{gathered} 6=2\times3 \\ 8=2\times2\times2=2^3 \end{gathered}

Next, pick the highest powers for each of the numbers:

\begin{gathered} \text{LCM}=2^3\times3 \\ =8\times3 \\ =24 \end{gathered}

5 0
1 year ago
Suppose you have a 6-face unfair dice with numbers 1,2,3,4,5,6 on each of its faces. If the probability distribution of throwing
kotegsom [21]

Answer:

D is correct

Step-by-step explanation:

Here, we want to select which of the options is correct.

The correct option is the option D

Since the die is unfair, we expect that the probability of each of the numbers turning up

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However, we should also expect that if we add the chances of all the numbers occurring together, then the total probability should be equal to 1. But this does not work in this case;

In this case, adding all the probabilities together, we have;

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= 5(1/12) + 1/2 = 5/12 + 1/2 = 11/12

11/12 is not equal to 1 and thus the probability distribution cannot be correct

4 0
3 years ago
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