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4 years ago

How to factorise by grouping for 7a, d and h

Mathematics

2 answers:

asambeis [7]4 years ago

7 0

Step-by-step explanation:

x2 + 4x + ax + 4a

x2 + ax + 4x + 4a

x (x + a) + 4 (x + a)

:(x + 4)(x+a)

x2+2x-ax-2a

x2-ax+2x-2a

x (x-a)+2 (x-a)

:(x+2)(x-a)

x2-2bx-5x+10b

x2-5x-2bx+10b

x (x-5)-2b(x-5)

:(x-2b)(x-5)

Maksim231197 [3]4 years ago

5 0

Answer:

You have to take out the common terms :

Question A,

${x}^{2} + 4x + ax + 4a$

$= x(x + 4) + a(x + 4)$

$= (x + a)(x + 4)$

Question D,

${x}^{2} + 2x - ax - 2a$

$= x(x + 2) - a(x + 2)$

$= (x - a)(x + 2)$

Question H,

${x}^{2} - 2bx - 5x + 10b$

$= x(x - 2b) - 5(x - 2b)$

$= (x - 5)(x - 2b)$

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Step-by-step explanation:

* Lets explain how to solve the problem

Part A

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- Bus B leaves every 15 minutes

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