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mixer [17]
3 years ago
5

One day, a person went to a horse racing area. instead of counting the numbers of humans and horses, he counted 74 heads, and 19

6 legs. how many humans and horses were there?
PLs i need help
Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer: there are 50 humans and 24 horses.

Step-by-step explanation:

Let x represent the number of humans in the horse racing area.

Let y represent the number of horses in the horse racing area.

He counted 74 heads. A human has one head and a horse also has one head. It means that

x + y = 74

He counted 196 legs. A human has 2 legs and a horse has 4 legs. It means that

2x + 4y = 196 - - - - - - - -- - -1

Substituting x = 74 - y into equation 1, it becomes

2(74 - y) + 4y = 196

148 - 2y + 4y = 196

- 2y + 4y = 196 - 148

2y = 48

y = 48/2 = 24

x = 74 - y = 74 - 24

x = 50

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6m+7n+5m−3n simpified
diamong [38]

Answer:

11m + 4n

Step-by-step explanation:

when two numbers with the same variable are added together or subtracted the result is just the numbers added or subtracted. So you can add 6m and 5m to get 11m. and you can subtract 3n from 7n to get 4n

11m + 4n

6 0
2 years ago
Find the 11th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.
marta [7]
I think you mean,

\sum_{i=1}^{\infty}(7i+22)

You can use the usual formula,

S_{k}=\frac{k}{2}(a_1+a_k)

That in this case is,

S_{11}=\frac{11}{2}(29+99)=704

Where I have used,

a_k=7\cdot k +22
3 0
3 years ago
Rob is saving to buy a new MP3 player. For every $16 he earns babysitting, he saves $7. On Saturday, Rob earned $48 babysitting.
mart [117]
He saved 7(3), which is equal to 21 dollars saved. Hope it helps!
5 0
4 years ago
Due in 5 mins help please!!!
gizmo_the_mogwai [7]

Answer:

answer B is correct answer!

I think so

5 0
3 years ago
The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar
podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}

So, we have:

d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50

d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50

Let the 4th vertex be (x,y)

So, we have:

d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50

d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50

Equate d3 and d4

\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}

Take the square of both sides

(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2

Expand

1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2

Evaluate the like terms

1 + 2x  + 16 + 8y  = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)

Read more about rhombus at:

brainly.com/question/20627264

#SPJ1

8 0
2 years ago
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