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2 years ago

I'm having a hard time solving this May I please have an explanation

Mathematics

2 answers:

Irina-Kira [14]2 years ago

7 0

Answer:

e = 9

Step-by-step explanation:

4e - 10 = 2e + 8

=> 4e + (-2e) - 10 = 2e + (-2e) + 8

=> 2e -10 = 8

=> 2e -10 + (+10) = 8 (+10)

=> 2e = 18

=> 2e/2 = 18/2

=> e = 9

Hope this helps!

Marina CMI [18]2 years ago

5 0

Answer:

e = 9

Step-by-step explanation:

ok e is just x, so we have to get it alone

4e - 10 = 2e + 8

We move the 2 since its smaller than the 4, and we move it two the other side. 4-2=2 so the new e is 2, now that 8 is alone (since we moved the 2), we cant be having the e with the -10... like this..

2e - 10 = 8, so we now add 10 so it can go with the 8, the new equation is this..

2e = 18

18/2 = 9

simple explanation

4e - 10 = 2e + 8

2e = 18

e = 9

(does that make sense)

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Step-by-step explanation:

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3 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

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Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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3 years ago

Read 2 more answers

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Answer:

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3 years ago

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Answer: Your answers ×=5 !

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago