$\frac{8}{11}(n-10)=64\\\\\frac{8(x-10)}{11}=64\\ 8(x-10) = 64(11)\\8(x-10) = 704\\8x-80 = 704\\8x= 704+80\\8x=784\\\\\frac{8x}{8}=\frac{784}{8} \\x=98$

7 0

3 years ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

2 years ago

Put these numbers in order from greatest to least<br> 6/8, 0.12, and -0.25

Setler [38]

This is the answer -0.25,0.12,6/8

4 0

3 years ago