I think this is right, i don't know for sure though. y=-x+(1)/(3)
Answer:
111 / 190
Step-by-step explanation:
Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;
![12 / 20 * 11 / 19 = \frac{33}{95},\\Probability of Drawing 2 Liquorice = \frac{33}{95}](https://tex.z-dn.net/?f=12%20%2F%2020%20%2A%2011%20%2F%2019%20%3D%20%5Cfrac%7B33%7D%7B95%7D%2C%5C%5CProbability%20of%20Drawing%202%20Liquorice%20%3D%20%5Cfrac%7B33%7D%7B95%7D)
Apply this same concept to each of the other sweets;
![5 / 20 * 4 / 19 = \frac{1}{19},\\Probability of Drawing 2 Mint Sweets = 1 / 19\\\\3 / 20 * 2 / 19 = \frac{3}{190},\\Probability of Drawing 2 Humbugs = 3 / 190](https://tex.z-dn.net/?f=5%20%2F%2020%20%2A%204%20%2F%2019%20%3D%20%5Cfrac%7B1%7D%7B19%7D%2C%5C%5CProbability%20of%20Drawing%202%20Mint%20Sweets%20%3D%201%20%2F%2019%5C%5C%5C%5C3%20%2F%2020%20%2A%202%20%2F%2019%20%3D%20%5Cfrac%7B3%7D%7B190%7D%2C%5C%5CProbability%20of%20Drawing%202%20Humbugs%20%3D%203%20%2F%20190)
Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;
![33 / 95 + 1 / 19 + 3 / 190 = \frac{79}{190},\\1 - \frac{79}{190} = \frac{111}{190}\\\\](https://tex.z-dn.net/?f=33%20%2F%2095%20%2B%201%20%2F%2019%20%2B%203%20%2F%20190%20%3D%20%5Cfrac%7B79%7D%7B190%7D%2C%5C%5C1%20-%20%5Cfrac%7B79%7D%7B190%7D%20%3D%20%5Cfrac%7B111%7D%7B190%7D%5C%5C%5C%5C)
The probability that the two sweets will not be the same type of sweet =
111 / 190
Hello! I would love to help!
Okay, we know that Raphel has to pay 3,000 dollars in a certain amount of months. Let's let "m" represent the amount of months it will take him.
Now, if we know that he saves 340 dollars a month, we can multiply the unknown amount of months, "m" by 340 to find how many will get 3000.
Here's our equation:
340m = 3000
Alright let's solve for m.
Divide both sides by 340.
340m/340= m
3000/340=8.824
So know we know m= 8.824, or exactly 8.824 months to save 3000 dollars.
However, it is really hard to count 8.824 parts of a month. Let's round it to the nearest whole, nine.
So, that means your answer is 9 months!
Hope this helped! Comment if you have questions!
Answer:
$15,264 cost amount on new advertising.
Shown as new equation that includes (original + new customer base)
n3=15264a
Step-by-step explanation:
First we have to find original amount of customers as 3 represents a multiple of n
n3=13824a
n3 means n x 3 then customer base is one third
= 1/3 x 13,824 = 4608 original customers per year
= 4608 original customers +480 new customers
4608 + 480 = 5088 total orig+initial customers
5088 x 3 = 15264 cost
= ($)15,264 cost
new equation
n3=15264a
Answer:
Step-by-step explanation:
C