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Blizzard [7]
3 years ago
5

A surf shop charges $6 to rent a wetsuit and $12 per hour to rent a surfboard. Write a function to model the cost, c, to rent a

wetsuit and surfboard for h hours. Enter the correct function in the box.
Mathematics
1 answer:
Over [174]3 years ago
8 0

C = 6 + 12^{x}

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There are 36 people in a fitness studio . 3/8 of the people lifted weights , 1/3 of the people did cross training , and the rema
irina1246 [14]
1 - 3/8 - 1/3 = 24/24 - 9/24 - 8/24 = 7/24

Answer: 7/24
8 0
3 years ago
A park is rectangular with a length of 2/3 miles. If the area of the park is 3/9 square miles, what is its width? Input your ans
adelina 88 [10]

Answer:

6/9 miles

Step-by-step explanation:

4 0
3 years ago
Explain why one column in a hundredths grid is equal to one column in a tenths grid.
fomenos
In a hundredths grid - square
In a hundredths grid, there are 10 blocks in each column. 10/100 = 10%. So one column is equal to 10%.
In a tenths grid- square
In a tenths grid, there is one block in each column. So 1/10 blocks = 10%. 
10/100 can simplify into 1/10. This is why both grids are equal. They are both equivalent fractions. Both grids have columns that equal 10%. 
8 0
3 years ago
What is the following quotient?
seropon [69]

Answer:  Choice B) \frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\

==========================================

Work Shown:

\frac{5}{\sqrt{11}-\sqrt{3}}\\\\\\\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{(\sqrt{11})^2-(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{11-3}\\\\\\\frac{5\sqrt{11}+5\sqrt{3}}{8}\\\\\\

This shows why choice B is the answer.

---------------

Explanation:

  • In the second step, I multiplied top and bottom by (\sqrt{11}+\sqrt{3})
  • This is so we can apply the difference of squares rule in step 3. The difference of squares rule is (x-y)(x+y) = x^2-y^2.
  • In step 4, the square roots cancel out with the squaring operation. The two operations are inverses of one another, which is why they cancel.

So in general, if the denominator is \sqrt{a}-\sqrt{b} and you want to rationalize the denominator, then you should multiply top and bottom by \sqrt{a}+\sqrt{b}. The same applies in reverse as well.

This leads to the denominator becoming (\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}) = (\sqrt{a})^2-(\sqrt{b})^2 = a-b

Keep in mind that a \ge 0 and b \ge 0

4 0
3 years ago
the length of the rectangle is measured as 370mm correct to 2 significant figures.a) what is the upper bound for the length?the
ivanzaharov [21]

Answer:

a) 375

b) 7062.75 mm²

Step-by-step explanation:

b) We need to find the shortest possible width and length to get the smallest possible area.

To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.

The boundaries are, therefore: 19.35 - 19.45

As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.

And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:

365 * 19.35 = 7062.75 mm²

7 0
3 years ago
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