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3241004551 [841]
4 years ago
5

Which is a counterexample for the conditional statement? If a square has side length s, then the perimeter is less than the area

. s = 3 s = 5 s = 7 s = 9
Mathematics
2 answers:
olga_2 [115]4 years ago
5 0
S=3. the perimeter, 12, is greater than the area, 9
Soloha48 [4]4 years ago
4 0

Answer:

Side length s = 3 is the counter-example for the given statement.

Step-by-step explanation:

We are given that the side length of a square = s.

Now, we know that,

Perimeter of a square = 4s

Area of a square = s^2

Then, the table showing the perimeter and area of a square for different side length is given by,

Side length (s)              Perimeter = 4s                          Area = s^2

       3                                        12                                         9

       5                                        20                                       25

       7                                        28                                        49

       9                                        36                                        81

<em>Now, we need a counter-example for the statement,</em>

'If the side length of a square is 's', then the perimeter is less than the area'.

From the table, we see that,

<em>When the side length of the square is 3, then perimeter = 12 > 9 = area.</em>

<h3>Thus, side length s = 3 is the counter-example for the given statement.</h3>
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