11+7=18
11*7=77
i hope that my answer helps
A 0.13 sec and a 86 kVp technical changes are the changes that would have to produce the radiographic density and the contrast that are more similar to the original.
<h3>What is the radiographic density?</h3>
The radio graphic density can de defined to be the total amount or the overall darkening that can be found in a particular radiograph. This is usually known to have a certain type of density range that lies between 0.3 to 2.0 density.
When there is a density that is less than 0.3, the problem is basically because there is the issue of the density which would be found at the base and the fact that the film that is being used has fog in it.
It is known that based on the values that we have here the density and contrast would have to be of the given kvp of 86 and 0.13 seconds in order to be said to be similar to the original.
Read more on the radiographic density here:
brainly.com/question/14332593
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Let’s make an equation 5x=15.25. We should get x by itself by dividing both sides by 5. Which should leave x=3.5, which would mean he’d have to run faster, so no. It’s not reasonable
