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3 years ago

9

The length of an object in feet is equal to 3 times its length in yards. The length of a water slide is 48 feet. Write and solve

a multiplication equation to find the length of the water slide in yards.

1 answer:

jolli1 [7]3 years ago

7 0

Answer:

144

Step-by-step explanation:

2

48 8x3=24 8 16 24

x 3 4x3=12+2=14 4 8 12 13 14

____

144

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1. Use the graph of the rational function

Mrrafil [7]

Answer:

As $x \to -3^{+}, f(x) \to -\infty$

Step-by-step explanation:

Given:

From the graph, we can conclude that:

The function has vertical asymptotes at $x=-3\ and\ x=2$

The function has horizontal asymptote at $f(x)=0$

Vertical asymptotes are those values of 'x' for which the functions tends towards infinity. Horizontal asymptote is the value of the function as the 'x' value tends to infinity.

Now, as $x \to -3^{+}$ means the right hand limit of the function at $x=-3$

From the graph, the right hand limit is the right side of the asymptote of the function at $x = -3$ . The right side shows that the function is tending towards negative infinity.

Therefore, As $x \to -3^{+}, f(x) \to -\infty$

4 0

3 years ago

Evaluate (-9)+9 <br> please

Nookie1986 [14]

The answer should be 0

7 0

2 years ago

Read 2 more answers

0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

7 0

2 years ago

What is 52 divided by 8 incluing remainder?

joja [24]

8*6=48. 8*7=56. So the highest multiplication you can go without exceeding the value of 52 is 8*6. You then need to subtract 52 by 48 to find the remainder. 52-48=4. So the answer would be 48 remainder 4

8 0

2 years ago

Find sin(α) in the triangle.

cluponka [151]

$\frac{20}{29}$ Answer:

sin α = $\frac{20}{29}$

Step-by-step explanation:

sin α = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{20}{29}$

6 0

2 years ago