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babunello [35]
3 years ago
13

You purchase x number of balloons for your party. You distribute them evenly among 8 tables. While you are finishing up with you

r decorations, 2 balloons pop. Is it true that each table will now have x − 2 8/2 balloons? Explain why or why not. someone help plzz
Mathematics
2 answers:
kifflom [539]3 years ago
6 0

Answer:

That expression is not true. To evenly distribute the balloons you use x/8. Then you subtract 2 balloons from that total amount. The subtraction must be done after the division. There will not be the same number of balloons at each table.

Step-by-step explanation:

It was the sample answer.

saul85 [17]3 years ago
4 0

Answer:

No, it's just maximum of two tables that lost balloon so there is no way it affected each table.

Step-by-step explanation:

Number of balloons purchased= x

Number of tables = 8.

Each table has = x/8 balloons

If 2 balloons pop.

Let's assume it's just from a table

That table has( x/8 -2)

If it's from 2 table

The two table has

(X/8-1) for both tables

But the total balloon remaining = x-2

There is no particular equation that can describe the gallon on each table because it's only two balloons that popped.

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Give an example of each of the following, or argue that such a request is impossible.
Masteriza [31]

Answer and Step-by-step explanation:

Solution:

(a) Let (bn) be a bounded sequence of (an) then, Bolzano- Weierstrass theorem,

(bn) contains a subsequence that is converges.

(b) The sequence :

Xn = 1 + (-1) n / 2 + 1/n

Clearly, (xn) does not contain 1 or 0.

If we take sequence (x2n), then it converges to 1 and when we take sequence (x2n+1),

Then it converges to 0.

(c) The sequence:

1

1,1/2

1, 1/2, 1/3

1, 1/2, 1/3, 1/4

i.e

(xn) = (1,1/2, 1, 1/2, 1/3, …)

Then, the subsequence (xn) that is identically ½ in second column and 1/3 is third column and so on.

It has sub sequence that converges to every point in infinite set {1, 1/2, 1/3, 1/4, 1/5…}.

(d) The sequence

{1, 1/2, 1/3, 1/4, 1/5…}

if we take sequence of given set, then, this set converges to zero. This is not contained in it.

If (xn) converges to every point in set {1, 1/2, 1/3 …} then there exists subsequence which converges to 0. And 0 does not belong to given set.

3 0
3 years ago
When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n + 1/5n = 24. What is the v
Zielflug [23.3K]
The answer is 20 since 1/5 of 20 is 4, and 20 + 4 = 24.
7 0
3 years ago
Read 2 more answers
The mean rent of a 3-bedroom apartment in Orlando is $1300. You randomly select 10 apartments around town. The rents are normall
lana [24]

Answer:

96.49% probability that the mean rent is more than $1100

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1300, \sigma = 350, n = 10, s = \frac{350}{\sqrt{10}} = 110.68

What is the probability that the mean rent is more than $1100?

This is 1 subtracted by the pvalue of Z when X = 1100. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1100 - 1300}{110.68}

Z = -1.81

Z = -1.81 has a pvalue of 0.0351

1 - 0.0351 = 0.9649

96.49% probability that the mean rent is more than $1100

7 0
3 years ago
Mrs.gauthier plans to take her class on 2 field trips this year there are 23 students in her class and each field trip will cost
Alina [70]

If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5

1st trip- $115

And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5

2nd trip- $115

To find out the total of both trips youd add 115+115/

In total, for both trips it will cost $230 dollars.

7 0
3 years ago
Solve for a. 1/5(25−5a)=4−a
aalyn [17]
1/5(25-5a)=4-a
⇔5-a=4-a
<span>NO SOLUTION</span>
3 0
3 years ago
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