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4 years ago

Place value for 987,164.302

2 answers:

8 0

9 is in the hundred thousands place, 8 is in the ten thousands place, 7 is in the thousands place, 1 is in the hundreds place, 6 is in the tens place, 4 is in the ones place.

kozerog [31]4 years ago

6 0

Nine-hundred eighty-seven thousand, one-hundred sixty-four and three tenths, two-thousandths.

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Solve the following equation by completing the next two lines (showing all work ) X + 6 = 10

WITCHER [35]

Answer:

x=10-6

x=4

Step-by-step explanation:

for which level

6 0

3 years ago

Solve for x 4x – 4<8 AND 9x +5 > 23

Leno4ka [110]

Answer:

x<3 AND x>2

Step-by-step explanation:

First, 4x-4<8. Adding 4 to both sides, 4x<12, and dividing by 4, x<3.

Next, 9x+5>23. Subtracting 5 from both sides, 9x>18, and dividing by 9, x>2.

Therefore, x<3 AND x>2.

4 0

3 years ago

Mr.Manciel is planning an event at a local hotel. The hotel owner told him that the dance floor in the ballroom is about 1,500 s

murzikaleks [220]

Yes it was reasonable. I say it is resonable because if you multiply 44 times 25 it is 1,100 so the estimate was close enough

8 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

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I need help I will give brainiest

zhenek [66]

It’s B !!!!!!!!!!!!!!!!!!!!!!

8 0

3 years ago

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