Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Answer:
Transitive property of equality
Step-by-step explanation:
By the definition of transitivity, a relation R is said to be transitive if (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R.
If p = q, q = r then p = r.
Here, we have given that if ZXY = FDE and FDE = CAB, then, ZXY = CAB.
Therefore, it shows the transitive property of equality.
Answer:
1:44
Step-by-step explanation:
You can subtract 32 minutes from 2:32 to get 2:00.
Since you only subtracted 32, subtract 16 (16+32=48) from 60, since 60 minutes is one hour, to get 1:44
Find the mean without the outlier <br>
15, 34, 38, 42, 43, 36, 40, 35, 36, 38,
Temka [501]
Is real confusing with this outliers
The answer is A because its simple reading. Are you 4? Because this is easy smh