<h3>
Answer: D) One solution</h3>
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Work Shown:
2(b+3)-17 = 3b-7+b
2b+6-17 = 4b-7
2b-11 = 4b-7
-11+7 = 4b-2b
-4 = 2b
2b = -4
b = -4/2
b = -2
There is one solution and it is b = -2
A quick way to tell we have one solution is to note that both sides are a linear expression, and that the slopes of each linear expression are different values. If you had two lines with the same slope, then you'd have either parallel lines or coinciding lines (leading to no solutions and infinitely many solutions respectively). When you have two lines with two different slopes, then they are guaranteed to intersect only once. That intersection point is the solution.
Answer:
![=5x^{2} +2x-4-(2x^{2} +6x-6)\\=5x^{2} +2x-4-2x^{2} -6x+6\\=5x^{2} -2x^{2} +2x-6x-4+6\\=3x^{2} -4x+2](https://tex.z-dn.net/?f=%3D5x%5E%7B2%7D%20%2B2x-4-%282x%5E%7B2%7D%20%2B6x-6%29%5C%5C%3D5x%5E%7B2%7D%20%2B2x-4-2x%5E%7B2%7D%20-6x%2B6%5C%5C%3D5x%5E%7B2%7D%20-2x%5E%7B2%7D%20%2B2x-6x-4%2B6%5C%5C%3D3x%5E%7B2%7D%20-4x%2B2)
Step-by-step explanation:
Hence,5x²+2x-4 and 2x²+6x-6 are the two polynomials.
To create them:
Let,5x²+2x-4 be the first polynomial and x be the another
Now, we have,
→5x²+2x-4-x=3x²-4x+2
→5x²+2x-4-(3x²-4x+2)=x
→5x²+2x-4-3x²+4x-2=x
→x=3x²-4x+2
Answer:
x=-1
Step-by-step explanation:
5x-7=-12
add 7 to both sides
5x=-5
divide both sides by 5
x=-1
Infinity raised to any number greater than 1 is always equal to infinity. But if infinity is raised to 0, then the result is indeterminate. Normally, if any number is raised to 0 is 1 but it is different for infinity.
Answer:Undefined
Step-by-step explanation: