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fgiga [73]
3 years ago
9

michelle lives with 2 brothers, 3 sisters, her mother, and her father. including Mitchell, 3/4 of her family likes to go swimmin

g. How many people like to go swimming in Michelle's family?
Mathematics
2 answers:
ruslelena [56]3 years ago
8 0
Michelle(1)+bros(2)+sisters(3)+mom(1)+Pop(1)=8
3/4 of 8 = 6
So, 6 people in Michelle's family like to go swimming
olya-2409 [2.1K]3 years ago
5 0
3/4 = 6/8 so your answer is 6
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I need to know this geometry answer.
STatiana [176]
2x + 1.5x +20 = 90 
3.5 x = 90-20 
3.5 x = 70 
x = 70/3.5 
x = 20 
angle DAE = 2*20 = 40 
angle CAD = 1.5*20 +20 = 50
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3 years ago
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Number line question PLEASE HELP
AleksandrR [38]
The answer is
A) 3 1/4 feet
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3 years ago
Anyone know? Will mark brainliest if correct!
almond37 [142]

Answer:

B

Step-by-step explanation:

using the two points, you can find the slop using rise over run. For every two up, you go three over to the left. Your slope is -2/3, which means the only possible answer is B

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3 years ago
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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
2 years ago
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Hii guys I need help with this I took a screenshot of it.
eduard

Answer:

x <= 9

Step-by-step explanation:

x -15 <= -6

+15. +15

x <=9

8 0
2 years ago
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