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3 years ago

Write the word sentence as an equation. 11 more than a number q is negative 15.

Mathematics

1 answer:

GaryK [48]3 years ago

4 0

11 + q = -15, simple as that.

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I need help with question four and the instructions for the equations or just solve the systems of simultaneously equation using

Sliva [168]

Answer:

x = 1\2 and y = 0

Step-by-step explanation:

8x + 3y = 4 * 5\3

14x - 5y = 7 * 1

40\3x + 5y = 20\3 -------- 1

14x - 5y = 7 ----------------- 2

add equation 1 and 2

82\3x = 41\3

x = 41 3

3 * 82

x = 1\2

subtitute 1\2 for x in equation 2

14\2 - 5y = 7

7 - 5y = 7

5y = 7 - 7

y = 0\5

y = 0

thus x = 1\2 and y = 0

6 0

2 years ago

PLEASE HELP!! 50 POINTS!!!!!

OLEGan [10]

Answer:

3\2 is the marked

y cos x,=2

3\2=0.5

x=0.5*2=3.0

=3.0*2=6.0

6 0

2 years ago

You estimate that there are 45 marbles in a jar. The actual amount is 82 marbles. Find the percent error. Round to the nearest t

Nataly_w [17]

Answer:

45.1

Step-by-step explanation:

The original amount is 82

But the wrong amount is 45

So we will have to calculate the percentage for the error

82-45

So %error= 37/82 ×100

=3700/82

=45.121~45.1( to nearest tenth)

So the final answer is 45.1%

6 0

3 years ago

Factorise 3<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="la

PilotLPTM [1.2K]

(x+1)x(3x+2) is the answer

5 0

3 years ago

Find the quotient of these Complex Numbers. (5-i) / (3+2i)

JulsSmile [24]

Let the given complex number

z = x + ix = $\dfrac{5-i}{3+2i}$

We have to find the standard form of complex number.

Solution:

∴ x + iy = $\dfrac{5-i}{3+2i}$

Rationalising numerator part of complex number, we get

x + iy = $\dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}$

⇒ x + iy = $\dfrac{(5-i)(3-2i)}{3^2-(2i)^2}$

Using the algebraic identity:

(a + b)(a - b) = $a^{2}$ - $b^{2}$

⇒ x + iy = $\dfrac{15-10i-3i+2i^2}{9-4i^2}$

⇒ x + iy = $\dfrac{15-13i+2(-1)}{9-4(-1)}$ [ ∵ $i^{2} =-1$ ]

⇒ x + iy = $\dfrac{15-2-13i}{9+4}$

⇒ x + iy = $\dfrac{13-13i}{13}$

⇒ x + iy = $\dfrac{13(1-i)}{13}$

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0

3 years ago