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nikitadnepr [17]
3 years ago
14

Write the word sentence as an equation. 11 more than a number q is negative 15.

Mathematics
1 answer:
GaryK [48]3 years ago
4 0
11 + q = -15, simple as that.

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His gross pay will be 9%
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Decide whether the two equations are equivalent 7v - 3/2 = 5 14v-3=15
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I think they are equivalent
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Find g(x), where g(x) is the reflection across the x-axis of f(x)=<br> –<br> 4(x–10)2+3.
Dahasolnce [82]
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3 0
3 years ago
The joint density function for a pair of random variables X and Y is given. f(x, y) = Cx(1 + y) if 0 ≤ x ≤ 4, 0 ≤ y ≤ 4 0 otherw
frozen [14]

Answer:

A) C = 1/96

B) P(x<=1, y<=1) = 1/128 or 0.0078125 to 7 places

C) P(x+y<=1) = 5/2305, or 0.0021701 to 7 places

Step-by-step explanation:

f(x,y) = C x (1+y)

A)

To find C, we need to integrate the volume under region bound by

0 <= x <= 4, and

0 <= y <= 4

This volume equals 1.0.

Find integral,

int( int(f(x,y),x=0,4), y = 0,4) = 96C

therefore C = 1/96

or

F(x,y) = x (1+y) / 96  ............................(1)

B)

P(x<=1, y<=1)

Repeat the integral, substitute the appropriate limits,

P = int( int(F(x,y),x=0,1), y = 0,1)

= 1/128 or 0.0078125

P(x<=1, y<=1) = 1/128 or 0.0078125 to 7 places

C)

P(x+y<=1)

From the function, we know that this is going to be less than one half of the probability in (B), closer to 1/4 of the previous.

It will be again a double integral, as follows:

P = int( int(F(x,y),x=0,1-y), y = 0,1)

= 5/2304

= 0.0021701 (to 7 decimals)

P(x+y<=1) = 5/2305, or 0.0021701 to 7 places

8 0
4 years ago
A loan processing office receives 4 loan requests every hour. The office has 2 departments. It takes the first department on ave
jenyasd209 [6]

Answer:

On average how many requests are in the first department (including those who are waiting) is 1.32.

Step-by-step explanation:

In this case, use the Little's law of queuing theory.

The Little's law states that the average number of customers in a fixed system (L) is equal to the average effective arrival rate (λ) multiplied by the average time a customer spends in the system (W).

The number of requests per hour in the 1st department is, λ₁ = 4.

It is provided that 20% are rejected directly by the 1st department without going into the 2nd department.

Then the number of requests per hour is, λ₂ = 4\times 80\%=4\times0.80=3.2

The average time a customer spends in the 1st department,

W₁ = 20 minutes = 0.33 hours.

The average time a customer spends in the 1st department,

W₂ = 60 minutes = 1 hour

On average how many requests are in the first department (including those who are waiting) is:

<em>L</em> = λ₁ × W₁

  = 4 × 0.33

  = 1.32

Thus, on average how many requests are in the first department (including those who are waiting) is 1.32.

6 0
4 years ago
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