Answer:
segment AD
Step-by-step explanation:
LOD is the far side of the cube.
ABC is the left side.
So the intersection is the vertical EDGE AD, on the far-left.
Answer:
Angle between the two vectors is 135°
u•v = -12
Step-by-step explanation:
Given two vectors u = (4,0) and v = (-3,-3).
To find the angle between the two vectors we will use the formula for calculating the angle between two vectors as shown;
u•v = |u||v|cos theta
cos theta = u•v/|u||v|
theta = arccos (u•v/|u||v|)
u•v = (4,0)•(-3,-3)
u•v = 4(-3)+0(-3)
u•v = -12
For |u| and |v|
|u| = √4²+0²
|u| = √16 = 4
|v| = √(-3)²+(-3)²
|v| = √9+9
|v| = √18
|v| = 3√2
|u||v| = 4×3√2 = 12√2
theta = arccos(-12/12√2)
theta = arccos(- 1/√2)
theta = -45°
Since cos is negative in the second quadrant, theta = 180-45°
theta = 135°
To get u•v using the formula u•v = |u||v|cos theta
Given |u||v| = 12√2 and theta = 135°
u•v = 12√2cos 135°
u•v = 12√2× -1/√2
u•v = -12√2/√2
u•v = -12
For the diagram of the vectors, find it in the attachment below.
Answer:
a = 60
Step-by-step explanation:
90 + 30 = 120
120 - 180 = 60
Answer:
-3.5 or -6
Step-by-step explanation:
2x^2+19x+40=-2
2x^2+19x+40+2=0
2x^2+19x+42=0
2x^2+(12+7)x+42=0
2x^2+12x+7x+42=0
2x(x+6)+7(x+6)=0
(x+6)(2x+7)=0
either,
x+6=0
x=-6
or,
2x+7=0
2x=-7
x=-7/2
x=-3.5