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zaharov [31]
2 years ago
15

What is the equation of the line parallel to the given line with an x-intercept of 4? y = x +

Mathematics
2 answers:
Nady [450]2 years ago
8 0

Answer:

Step-by-step explanation:

The equation of the line parallel to

y = x

has a slope of m = 1

This means that the family of lines with the same slope are of the form

y = x - (a)

where  -a  represents the y intercept, and (a) the x- intercept

With a = 4, the equation intercepts the x axis at x = 4

Please see attached graph

Mice21 [21]2 years ago
5 0

Answer:

What is the equation of the line parallel to the given line with an x-intercept of 4?

y = 4 x +  -16

Step-by-step explanation:

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576 = 96 × 6
aliya0001 [1]

Answer:

D

Step-by-step explanation

A.96=6+576

B.576=96+6

C. 96=6×576

D. 576=96×6

5 0
2 years ago
Guys can you please to this thank
hram777 [196]
= 16 + 49 - 3(11)  - 4(10)
= 16 + 49 - 33 - 40
= -8
7 0
3 years ago
Question: A canary's beak is, at most, 20mm long. Which algebraic inequality represents this situation?
Paul [167]

Answer:

Option (1).

Step-by-step explanation:

Statement given states that "A canary's beak is, at most 20 mm long."

Word "at most" means "the maximum".

So at most length of the beak means "length of the beak is less than equal to 20 mm".

And the expression representing this statement algebraically will be,

x ≤ 20

Therefore, option (1) will be the correct option.

8 0
3 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
3 years ago
Rectangle a has area 40 cm square and length 8 cm. the area of rectangle b is one half the area of rectangle
lesya [120]
Area of rectangle b=1/2 area of rectangle a=40/2=20 cm²
Length=8 cm 
Width of rectangle b=20/8 =2.5 cm
5 0
2 years ago
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