Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
Answer:
1590.4 square ft
Step-by-step explanation:
r=30 so you need to multiply that by 25% (30*.25=7.5)
30-7.5=22.5
A= pi(r)^2
A=pi*(22.5)^2
A=506.25pi
A=1590.43 or 1590.4 (to the nearest tenth)
Answer: 1091
Step-by-step explanation: add the numbers
<h2>
Answer:</h2>
The values of x for which the given vectors are basis for R³ is:
<h2>
Step-by-step explanation:</h2>
We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.
We are given three vectors as:
(-1,0,-1), (2,1,2), (1,1, x)
The matrix formed by these vectors is:
![\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%262%261%5C%5C0%261%261%5C%5C-1%262%26x%5Cend%7Barray%7D%5Cright%5D)
Now, the determinant of this matrix is:
Hence,
Answer:
A) y=.50x+15
B) The graph would be a line starting in the bottom left corner and rising to the upper right, the start of the y axis would be 1, as it represents the miles, and the start of the x axis would be 0.50, as it represents the amount of money charged per mile.
C) If you apply the formula y=mx+b to the equation, you will see that 0.50 is the slope, and 15 is the y-intercept.
