Compute the permutation. A chemist has eight test tubes to examine. In how many orders can he do this examination? 16,777,216 20

Question

4 years ago

11

,160 40,320

1 answer:

Talja [164] · Answer 1 · 2021-11-11T20:20:28+03:00

Answer:

40,320

Step-by-step explanation:

He can pick any one of the eight for the first examination.

He can pick any one of the remaining 7 for the 2nd examination.

He can pick any one of the remaining 6 for the 3rd examination.

...

He can pick any one of the remaining 2 for the 7th examination.

There's one left for the 8th examination.

Thus, there are 8×7×6×5×4×3×2×1 = 8! = 40,320 different possible orders in which the tubes can be examined.