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3 years ago

Solve.. -x/6>3 A)x< -18 B)x<18 C)x>18 D)x> -18

Mathematics

1 answer:

ehidna [41]3 years ago

3 0

Answer:

x < -1/2

Step-by-step explanation:

Starting with -x/6>3, multiply both sides by -1/6, to remove fractions. Remember to reverse the direction of the inequality sign, which is required because we're multiplying -x/6>3 by a negative number.

x < 3(-1/6), or x < -1/2

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myrzilka [38]

Answer:

sorry I can't answer

Step-by-step explanation:

pls thanks me

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3 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

I missed the day we learned this, please help

love history [14]

Answer:

The slope is 1/3

Step-by-step explanation:

Take 2 points on the line, lets use (0,50) and (30,60)

x1 y1 x2 y2

Use slope formula:

y2 - y1 / x2 - x1

60 - 50 / 30 - 0

10 / 30

which can be simplified to:

1/3

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3 years ago

Using the slope formula, find the slope of the line through the given points.

UNO [17]

Answer:

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

= (-5--5)/ (9--8)

= (-5+5)/(9+8)

= 0/17

The slope it 0

This is a horizontal line because the y value doesn't change. If the y value doesn't change, the slope it zero.

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3 years ago

Lisa is making her famous chocolate chip brownies. The recipe calls for 2 cups of chocolate chips, but Lisa can only find her La

Ilia_Sergeevich [38]

Answer:

I think the answer is 8

Step-by-step explanation:

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3 years ago