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3 years ago

Solve whether the equation have 1 solution no solution or infinity solution

Mathematics

2 answers:

enot [183]3 years ago

6 0

Answer:

the solution to this problem is 392

Step-by-step explanation:

babymother [125]3 years ago

5 0

Steps to solving equations:
Simplify/combine the like terms
Isolate the variable (Get the variable on one side
Solve for the variable

-2y - 7 + 5y = 13 - 2y Simplify/Combine terms
3y -7 = 13 - 2y Isolate variable by adding 2y to both sides
5y - 7 = 13 Add 7 to both sides to get y alone on one side
5y = 20 Divide by 5 on both sides to solve for y
y = 4
You can check your answer by replacing y with 4 in the original equation.

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A random variable X has a Poisson distribution with a mean of 3. What is the probability that X P(1≤X≤3) ?.

frosja888 [35]

Answer:

P(1≤X≤3) = 0.5974

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 3

This means that $\mu = 3$

P(1≤X≤3) ?

$P(1 \leq X \leq 3) = P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

$P(1 \leq X \leq 3) = P(X = 1) + P(X = 2) + P(X = 3) = 0.1494 + 0.2240 + 0.2240 = 0.5974$

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HELP ASSAP WITH THIS QUESTION

lilavasa [31]

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Step-by-step explanation:

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