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zhuklara [117]
3 years ago
15

the line with a slope of 1/3 and a y- intercept of - 15 intersects the line passing through which of these pairs of points?

Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

Options (C), (D) and (E)

Step-by-step explanation:

Slope of the given line = \frac{1}{3}

Any line having same slope will be parallel to the given line otherwise the lines will intersect.

Therefore, we will find the slope of the lines passing through two points given in the options.

Option A

Slope of the line passing through (12, -13) and (15, -12)

m = \frac{y_2-y_1}{x_2-x_1}

   = \frac{-13+12}{12-15}

   = \frac{1}{3}

Therefore, both the lines are parallel having no point of intersection.

Option B

Slope = \frac{-9+7}{18-24}

          = \frac{1}{3}

Both the lines are parallel having no point of intersection.

Option C

Slope = \frac{-20+21}{15-18}

          = -\frac{1}{3}

Therefore, both the lines will intersect.

Option D

Slope = \frac{-15+14}{30-36}

          = \frac{1}{6}

Both the lines will intersect each other.

Option E

Slope = \frac{-11+10}{24-30}

          = \frac{1}{6}

Both the lines will intersect each other at a point.

Options (C), (D) and (E) are the correct options.

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Answer:

864 cubic inches

Step-by-step explanation:

Complete Question

A display case in the shape of a rectangular pyramid has a base that is 12 inches by 9 inches. It is 8 inches tall. What is the volume of the display case?

The volume of a rectangular pyramid =

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Volume of rectangular pyramid =

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3 0
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If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

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Step-by-step explanation:

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