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neonofarm [45]
3 years ago
8

How do I solve this

Mathematics
1 answer:
maw [93]3 years ago
8 0
Will you multiply 65×3
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0.60 10 000 % = 0.00006% 0 6 X 10-5% ayudemnea resolverlo
o-na [289]

Answer:

I dunno understand if what kind of opperation you're doing. Is there a multiplication?

<h3>Step-by-step explanation:</h3>

0.60 · 10,000 % = 0.00006 % · 0.6<em>x </em>· 10-5%

If it's a multiplication the answer will be

X = 150125000/ 9

3 0
3 years ago
The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion about 3/4 comes from tolls on
Rama09 [41]

Percent of turn pike is 75% and percent of parkway is 25%.

<u>Solution:</u>

Given, The state of New Jersey makes approximately $1.55 billion annually from tolls of the $1.55 billion

About \frac{3}{4} comes from tolls on the turnpike

Remaining \frac{1}{4} comes from tolls on the parkway  

<em><u>To find the percent of the total revenue from turnpike:</u></em>

\begin{array}{l}{\text { Percent of turnpike }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \text { of total revenue }}{\text { tot al revenue }} \times 100} \\\\ {=\frac{\frac{3}{4} \times \text { total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{3}{4} \times 100=3 \times 25=75 \%}\end{array}

<em><u>To find the percent of the total revenue from parkway:</u></em>

\begin{array}{l}{\text { Percent of parkway }=\frac{\text { amount from parkway }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \text { of total revenue }}{\text { total revenue }} \times 100} \\\\ {=\frac{\frac{1}{4} \times \text { total revenue}}{\text { total revenue }} \times 100} \\\\ {=\frac{1}{4} \times 100=25 \%}\end{array}

<em><u>Summarizing the results:</u></em>

Percent of turn pike is 75%

Percent of parkway is 25%

3 0
3 years ago
HELP!!!<br> what is x?<br> x2/4*=50
Gnoma [55]
Hello there. 

THe answer is x=100.

Plz branliest
5 0
3 years ago
Read 2 more answers
Find the Fourier series of f on the given interval. f(x) = 1, ?7 &lt; x &lt; 0 1 + x, 0 ? x &lt; 7
Zolol [24]
f(x)=\begin{cases}1&\text{for }-7

The Fourier series expansion of f(x) is given by

\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7

where we have

a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx
a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)
a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2

The coefficients of the cosine series are

a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx
a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)
a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}
a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}

When n is even, the numerator vanishes, so we consider odd n, i.e. n=2k-1 for k\in\mathbb N, leaving us with

a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}

Meanwhile, the coefficients of the sine series are given by

b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx
b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)
b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}
b_n=\dfrac{7(-1)^{n+1}}{n\pi}

So the Fourier series expansion for f(x) is

f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7
3 0
3 years ago
I graphed but do not understand, Please explain. Figure shown.
kodGreya [7K]

Answer:

its up.

Step-by-step explanation:

PLZ, MARK ME BRAINIIEST!!

8 0
3 years ago
Read 2 more answers
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