Answer:
62: 300l/hr
63: .018mi/s
64: .46qt/s
65: 298.2mi/hr
Step-by-step explanation:
62: 5x60=300
63: 68/60=1.13/60=.018
64:7gal=28qt 28/60=.467
65: 8km=4.97mi 4.97x60=298.2
Please provide more information.
Answer: 161 rupees.
Step-by-step explanation:
Use a percentage Calculator on the internet to find the solution.
1100 + 50
1150
(put into calculator)
Answer:
171 newspapers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How many newspapers should the newsstand operator order to ensure that he runs short on no more than 20% of days
The number of newspapers must be on the 100-20 = 80th percentile. So this value if X when Z has a pvalue of 0.8. So X when Z = 0.84.




So 171 newspapers.
Answer:
the volume is 196
Step-by-step explanation:
17x8=136
6x10=60
136+60=196