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pashok25 [27]
3 years ago
7

Please help! finding the area of each polygon

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0
Multiply length times width
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If m<BAD=102° and m<CAD=27°, what is m<BAC?
marissa [1.9K]
Angle BAC is 75 because you subtract 27 from 102.
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3 years ago
Evaluate (2-3) (4) - 9 -3.<br> -7<br> I<br> 11<br> 4
Delicious77 [7]

Answer:

-16

Step-by-step explanation:

8 0
3 years ago
onyango wishes to fence a rectangular research plot using 100 m of wire .one end of the plot has a wall already erected .calcula
earnstyle [38]

Answer:

1250 m²

Step-by-step explanation:

Let x and y denote the sides of the rectangular research plot.

Thus, area is;

A = xy

Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.

Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;

2x + y = 100

Thus, y = 100 - 2x

Since A = xy

We have; A = x(100 - 2x)

A = 100x - 2x²

At maximum area, dA/dx = 0.thus;

dA/dx = 100 - 4x

-4x + 100 = 0

4x = 100

x = 100/4

x = 25

Let's confirm if it is maximum from d²A/dx²

d²A/dx² = -4. This is less than 0 and thus it's maximum.

Let's plug in 25 for x in the area equation;

A_max = 25(100 - 2(25))

A_max = 1250 m²

5 0
3 years ago
Please help me if you think you're hot beautiful skinny funny kind please help me
ehidna [41]

Answer:

Step-by-step explanation:

y= -5x/2+1

3 0
2 years ago
Write the complex number in polar form:
emmasim [6.3K]

9514 1404 393

Answer:

  2√30 ∠-120°

Step-by-step explanation:

The modulus is ...

  √((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30

The argument is ...

  arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle

The polar form of the number can be written as ...

  (2√30)∠-120°

_____

<em>Additional comments</em>

Any of a number of other formats can be used, including ...

  (2√30)cis(-120°)

  (2√30; -120°)

  (2√30; -2π/3)

  2√30·e^(i4π/3)

Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).

__

At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)

6 0
3 years ago
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