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2 years ago

If the diameter of the circle is 11 inches, then the radius will be _____ inches.

Mathematics

2 answers:

Elodia [21]2 years ago

5 0

You divide 11 by 2.

radius = 11/2 = 5.5 inches

Hope this helps :)

satela [25.4K]2 years ago

4 0

5.5 its half the diameter

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A cell tower is located at and transmits a circular signal that covers three major cities. The three cities are located on the c

Lelu [443]

Answer:

$(x+8)^2 +(y-4)^2 = 25$

Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

$(x-h)^2 +(y-k)^2 = r^2$

From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this: $(x+8)^2 +(y-4)^2 = r^2$

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for $r^2$

$(-4+8)^2 +(7-4)^2 =25= r^2$

So then $r = \sqrt{25}=5$

And if we replace the second point we got this:

$(-13+8)^2 +(4-4)^2 = 25 =r^2$

And for the third point we have:

$(-8+8)^2 +(-1-4)^2 = 25 =r^2$

And we got the same result.

So then our final equation is given:

$(x+8)^2 +(y-4)^2 = 25$

4 0

3 years ago

My question is:

8090 [49]

Uh it's 5? I'm confused

8 0

3 years ago

Read 2 more answers

Where do I find my work I did with a tutor?

OlgaM077 [116]

It should come up as a notification. Check your messages or press “tutor” maybe even try reloading the page.

8 0

1 year ago

A cone and a triangular pyramid have a height of 9.3 m

Otrada [13]

Answer:

$x=17.1\ in$

Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

$\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]$