If the diameter of the circle is 11 inches, then the radius will be ____

lara31 [8.8K]

6w-10 represents the total amount of fence will need to complete the rectangle of fence in his yard. The fence will need two lengths and 2 widths to complete the rectangle. If the width is w, and the length is 2w-5, then the total for the rectangle would be w+w+2w-5+2w-5 which simplifies to 6w-10.

7 0

3 years ago

Read 2 more answers

Loretta grew 54 watermelons in her garden last year. This year, that number increased by 5/9. Which expression shows the number

Mars2501 [29]

Answer:

$54+\frac{5}{9}\times 54$

Step-by-step explanation:

We are given that

Loretta grew watermelons in her garden last year=54

We have to find the expression which shows the number of watermelons Loretta grew this year.

To find the expression which shows the number of watermelons Loretta grew this year by adding watermelons grew in her garden last year and number of watermelons increased .

According to question

5/9 of 54= $\frac{5}{9}\times 54$

Therefore, the expression which shows the number of watermelons Loretta grew this year

= $54+\frac{5}{9}\times 54$

6 0

2 years ago

Using y=mx+b find the slope for<br> 7) 8x + 3y = −9

malfutka [58]

Answer:

-8/3

Step-by-step explanation:

8x + 3y = - 9

Let's make y the subject of the formula.

y = - 9/3 - 8x/3

Rearrange

y = - 8x/3 - 3

The slope is the coefficient of x which is - 8/3

If you don't understand, please leave a comment

Please gimme brainliest

7 0

2 years ago

Many, many snails have a one-mile race, and the time it takes for them to finish is approximately normally distributed with mean

Mamont248 [21]

Answer:

a) The percentage of snails that take more than 60 hours to finish is 4.75%.

b) The relative frequency of snails that take less than 60 hours to finish is 95.25%.

c) The proportion of snails that take between 60 and 67 hours to finish is 4.52%.

d) 0% probability that a randomly-chosen snail will take more than 76 hours to finish

e) To be among the 10% fastest snails, a snail must finish in at most 42.32 hours.

f) The most typical 80% of snails take between 42.32 and 57.68 hours to finish.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 50, \sigma = 6$

a. The percentage of snails that take more than 60 hours to finish is

This is 1 subtracted by the pvalue of Z when X = 60.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 50}{6}$

$Z = 1.67$

$Z = 1.67$ has a pvalue 0.9525

1 - 0.9525 = 0.0475

The percentage of snails that take more than 60 hours to finish is 4.75%.

b. The relative frequency of snails that take less than 60 hours to finish is

This is the pvalue of Z when X = 60.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 50}{6}$

$Z = 1.67$

$Z = 1.67$ has a pvalue 0.9525

The relative frequency of snails that take less than 60 hours to finish is 95.25%.

c. The proportion of snails that take between 60 and 67 hours to finish is

This is the pvalue of Z when X = 67 subtracted by the pvalue of Z when X = 60.

X = 67

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{67 - 50}{6}$

$Z = 2.83$

$Z = 2.83$ has a pvalue 0.9977

X = 60

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 50}{6}$

$Z = 1.67$

$Z = 1.67$ has a pvalue 0.9525

0.9977 - 0.9525 = 0.0452

The proportion of snails that take between 60 and 67 hours to finish is 4.52%.

d. The probability that a randomly-chosen snail will take more than 76 hours to finish (to four decimal places)

This is 1 subtracted by the pvalue of Z when X = 76.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{76 - 50}{6}$

$Z = 4.33$

$Z = 4.33$ has a pvalue of 1

1 - 1 = 0

0% probability that a randomly-chosen snail will take more than 76 hours to finish

e. To be among the 10% fastest snails, a snail must finish in at most hours.

At most the 10th percentile, which is the value of X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 50}{6}$

$X - 50 = -1.28*6$

$X = 42.32$

To be among the 10% fastest snails, a snail must finish in at most 42.32 hours.

f. The most typical 80% of snails take between and hours to finish.

From the 50 - 80/2 = 10th percentile to the 50 + 80/2 = 90th percentile.

10th percentile

value of X when Z has a pvalue of 0.1. So X when Z = -1.28.

$Z = \frac{X - \mu}{\sigma}$

$-1.28 = \frac{X - 50}{6}$

$X - 50 = -1.28*6$

$X = 42.32$

90th percentile.

value of X when Z has a pvalue of 0.9. So X when Z = 1.28

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 50}{6}$

$X - 50 = 1.28*6$

$X = 57.68$

The most typical 80% of snails take between 42.32 and 57.68 hours to finish.

5 0

3 years ago

Neil and Nancy are married with two children at home and a mortgage. Neil's net pay per year is $56,000 and Nancy doesn't have a

jok3333 [9.3K]

Answer:

their current cash flow is negative since their expenses are higher than their income:

monthly net income = $56,000 / 12 = $4,667
monthly expenses = $1,500 + $3,500 = $5,000
monthly cash flow = ($333)

they have 3 options:

Option 1 (which I personally dislike) is that Neil contributes $4,000 less per year to his retirement account in order to balance their net income and expenses. The problem is that once he retires, his income will be much lower.
Option 2 is that they lower their expenses a little bit, only enough to balance their cash flows.
Option 3 is that Nancy gets a part time job, maybe a couple of hours per day which will allow her to earn money that can be used to cover some expenses.

Personally I believe that option 2 is the best, but if they definitely cannot lower their monthly expenses, then option 3 would probably fit them.

7 0

3 years ago

If the diameter of the circle is 11 inches, then the radius will be _____ inches.