I answered a similar problem yesterday.
In three coin tosses there are 8 possible outcomes:
H H H
H H T
H T H
T H H
T T H
T H T
H T T
T T T
Of those results, four out of the eight have at least 2 tails and so the probability is (4/8) or50%
If you need the probability of getting EXACTLY 2 tails then the probability is (3/8) or .375
Answer:
48
Step-by-step explanation:
B and C trisrct AD so
that means that
AB=BC=CD
M is the midpoint so AM =MD
M is also the midpoint of BC also so if MC equal 8 l, BM equal 8. We add 8 and 8 together to find the value of BC which equal 16. Since BC equal 16 and it trisects AD, AB equal 16 and CD equal 16. Add all together and we get 16+16+16=16×3=48
Think it's 4 because 5 factors and only number with 5 factors is 4 :p
