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White raven [17]
3 years ago
14

If f(x)=x^2-3 and

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
Since it is f of g you have to start by plugging in g(x) into f(x)

(4-3x)^2-3

Then just solve the equation

(4-3x)^2-3
(4-3x)(4-3x)-3 Square the binomial
8-12x-12x+9x^2-3 Combine like terms
5-24x+9x^2 Final answer
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Gianna has a two $3,000 one year CDs at different banks. Each compounds
sertanlavr [38]

Answer:

Option D

Step-by-step explanation:

To calculate compound interest we will use the formula :

A=P(1+\frac{r}{n})^{nt}

Where,

A = Amount on maturity

P = Principal amount = $3000

r = rate of interest = 8.4% = 0.084

n = number of compounding period = Monthly = 12

t = time = 1 year

Now put the values in the formula.

A=3000(1+\frac{0.08}{12})^{(12)(1)}

   = 3000(1+0.007)^{12}

   = 3000(1.007)¹²

   = 3000 × 1.08731066

   = 3261.93198 ≈ $3261.93

While the other bank compounds interest daily.

Therefore, n = 365

Now put the values in the formula with n = 365

=3000(1+\frac{0.084}{365})^{(365)(1)}

=3000(1+0.00023014)^{365}

=3000(1.00023014)^{365}

= 3000 × 1.08761958

= 3262.85874 ≈ $3262.86

Difference in the ending balance = 3262.86 - 3261.93

                                                       = $0.93

The difference in the ending balances of both CDs after one year would be $0.93.

8 0
3 years ago
11% as a decimal=<br><br> 200% as a decimal=<br> 20.07% as a decimal<br> 198.4% as a decimal
Hitman42 [59]
To convert from a percentage to a decimal, move the decimal twice to the left

11% = 0.11
200% = 2.00
20.07% = 0.2007
198.4% = 1.984

Hope this helps!
8 0
3 years ago
Read 2 more answers
Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)
Tems11 [23]

The slope of the tangent line to f at x=-1 is given by the derivative of f at that point:

f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}

Factorize the numerator:

2x^2-2=2(x^2-1)=2(x-1)(x+1)

We have x approaching -1; in particular, this means x\neq-1, so that

\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)

Then

f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4

and the tangent line's equation is

y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2

6 0
3 years ago
What is the place value for 3 in 6,035
bonufazy [111]
The place value in 6,035 is 30
5 0
3 years ago
If 13 = 4.5 -5k what is the value of k
USPshnik [31]

Answer:

K = negative 1.7

Step-by-step explanation:

4.5- 13 = -8.5

-8.5/5 = -1.7

4.5 - 5(-1.7) = 13

Hope this helped

7 0
3 years ago
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