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4 years ago

Here are the ingredients to make 12 shortcakes:

2 answers:

7 0

25/10=2.5 lots
2.5x12=30 shortcakes

500/50=10 lots
1000/200=5 lots
1000/200=5 lots
500/10=50 lots
so the maximum number of lots is 5
5x12=60 shortcakes

hope this helps

muminat4 years ago

7 0

So,

For a dozen shortcakes:
50g sugar
200g butter
200g flour
10 ml milk

Question #1:
If Liz used 25 ml milk, then she probably made 2.5 dozen shortcakes.

2.5(12) = 30

Liz made 30 shortcakes.

Question #2:
Robert's supplies:
500g sugar
1000g butter
1000g flour
500 ml milk

A dozen shortcakes takes
50g sugar
200g butter
200g flour
10ml milk

If he makes 5 dozen shortcakes, he will use

250g sugar
1000g butter (all of it)
1000g flour (all of it)
50ml milk

Robert cannot make more than 5 dozen shortcakes (60).

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What is the exact volume of this cone?

Studentka2010 [4]

Answer:

(b) 80/3π in³

Step-by-step explanation:

The volume of a circular cone is given by ...

V = 1/3πr²h . . where r is the radius (half the diameter) and h is the height

Your cone has r = 4 inches and h = 5 inches, so its volume is ...

V = (1/3)π(4 in)²(5 in) = 80/3π in³

The volume of the cone is exactly (80/3)π cubic inches.

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2 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

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3 years ago

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lora16 [44]

Answer:

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Step-by-step explanation:

we know that

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substitute

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3 years ago