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katrin [286]
3 years ago
12

X - Y = 11 2x + Y = 19 where do the lines cross

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0
Just solve the equations:
<span>A) X - Y = 11
B) 2x + Y = 19
Multiply A) by -2
</span>
<span>A) -2X  +2Y = -22 then add to B)
</span><span>B) 2x + Y = 19
3Y = -3
Y=-1
</span>
<span>A) X - -1 = 11
x = 10

</span>
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Answer:

Option (1)

Step-by-step explanation:

Given equation is,

2^x=1-3^x

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

2^{-0.75}=1-3^{-0.75}

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

2^{-1.25}=1-3^{-1.25}

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

2^{0.75}=1-3^{0.75}

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

2^{1.25}=1-3^{1.25}

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2.38 = -2.95

It's not true.

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6 0
3 years ago
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Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

This gives us:

a_{1} = 12( { -  \frac{1}{9} })^{0}

a_{1} = 12(1) = 12

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3 years ago
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Answer:

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