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Virty [35]
4 years ago
14

Can someone explain how to do this please?

Mathematics
1 answer:
Jobisdone [24]4 years ago
4 0

\bf \begin{cases} \boxed{y}=-2x\\\\ -x-y=4 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know what \boxed{y} is, let's substitute it in the 2nd equation}}{-x-\left( \boxed{-2x} \right)=4\implies -x+2x=4\implies x=4} \\\\[-0.35em] ~\dotfill\\\\ y=-2x\implies y=-2(4)\implies y=-8 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (4,-8)~\hfill

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Answer:

m < 36

yes, Jamie is correct.

Step-by-step explanation:

I've bolded the statements that you can put down to show your work

the maximum that Jamie is willing to practice for the week is 300 minutes, so you can start by creating an inequality for that.

total minutes throughout the week < 300

next, you know that a week is monday through friday + the weekend, and the amount of minutes Jamie will practice for the weekend is already given.

so, you can rewrite the earlier inequality like so

Monday through Friday practice + 120 < 300

since Jamie plans to practice the same amount of time (m) for each day, and there are 5 days between monday and friday, you can substitute values in the equation

5m + 120 < 300

simplify

5m < 300 - 120

5m < 180

m < 36

since half an hour is 30 minutes, the answer is yes, Jamie's claim is correct.

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