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Alchen [17]
3 years ago
14

tion. 6. A step occasionally required to repair damaged relationships is O A. looking at the problem from the other person's poi

nt of vievw. O B. deciding that the relationship isn't worth saving O C. changing the behavior that caused the problem O D. communicating honestly and openly about the problem. O Mark for review (Will be highlighted on the review page Previous Question Next Question Review My Answers Save & Exit
Computers and Technology
1 answer:
Marta_Voda [28]3 years ago
5 0
The answer to this question is b that's the answer
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If you were optimizing for performance and wanted to support potentially adding many new elements to an adt, then:
muminat

<span>If you were optimizing for performance and wanted to support potentially adding many new elements to an adt, then a list would allow faster addition of elements than an array. The object that contains the data of similar type is called an array. When the array is created, its length of array is established.</span>

7 0
4 years ago
Compare the applications below:
Lubov Fominskaja [6]

Answer:

i think it is B

Explanation:

6 0
4 years ago
Read 2 more answers
On the classic gameshow The Price Is Right, contestants must guess the price of an object (guesses are distinct). The winner is
Kruka [31]

Answer:

The program code is in explaination

Explanation:

Program code below.

def judge(auction,price):

"""

Function: Returns Name who auctioned very near to give price

Input :

auction : list of tuples

price : auction price

output: returns name of best auction amount holder

"""

diff = [] #storing differences between auctionist amount and price

count = 0

for each_pair in auction:

if each_pair[1]<=price:

diff.append(price-each_pair[1])

else:

count+=1

diff.append(each_pair[1])

if count == len(auction): #check for if no one have auctioned good amount

return None

else:

more_possibility_index = diff.index(min(diff)) #finding index of best amount from diff list

return auction[more_possibility_index][0]

auction = [('Alice',430),('Bob',538),('Carol',487),('David',550)]

price = 520

print(judge(auction,price))

I kept the output at the attachment.

3 0
3 years ago
Write a recursive function that calculates if two binary trees are similar?
ahrayia [7]

Answer:

bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.

{

   if(root1==NULL&&root2==NULL)//both trees are null means identical.

   return true;

   if(roo1 && root2)

   {

       if(root1->data==root2->data)//condition for recursive call..

       {

           return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);

       }

   }

   else

   return false;

}

Explanation:

In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.

If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.

else returning false.

5 0
3 years ago
Which principle suggests that specific single responsibility interfaces are better than one general purpose interface?
ElenaW [278]

Answer:Interface segregation principle

Explanation: Interface-segregation principle (ISP) is amongst the major principles of the object-oriented design which describes that none of the users/clients can be forced for indulging and depending on the unknown methods or methods that they don't have knowledge about.

It functions by making the interfaces visible to the user that specifically fascinates them and keeping other smaller interfaces.Interfaces are made by splitting process and making the small interfaces from them.

8 0
3 years ago
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