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RUDIKE [14]
2 years ago
12

The current standard for RFID is based off of Group of answer choices MIT standards IEEE standards ISO standards there is no agr

eement on a universal standard that’s accepted by all parties
Computers and Technology
1 answer:
mamaluj [8]2 years ago
4 0

Answer:

ISO standards

Explanation:

ISO / IEC 14443 is the ISO standard that covers RFID usage by devices.

EPCglobal - Electronics Product Code Global Incorporated is also another international standard that covers RFID. These two standards work together to standardize RFID products produced by manufacturers so that these products can be the same across different markets and manufacturers. Example I can purchase a tag from one manufacturer and a transceiver from another and they would function well together. There are also other standards for RFID but the above two are the biggest and most popular with ISO being the oldest.

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Which of the following would be least effective?
Goryan [66]

Answer:

Exponential

Explanation:

The growth of an exponential function will develop much faster than all other functions included in the options meaning the execution time will take longer. This makes exponential functions the least efficient.

4 0
2 years ago
Jamie has to enter names, grades, and scores of a group of students into a worksheet. Which option will Jamie use to describe th
Alona [7]

Answer:

a. labels

Explanation:

a. labels b. graphs c. numbers d. formulas

It is the labels, which is the title of each column. For one column we can have the names, for another column, we can have a label grade. and for the third column, we can have the label scores. And the others are the graphs, formulas and the numbers, which are not an option.

6 0
3 years ago
Description:
Nastasia [14]

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

<em>int convert(float miles) </em>

<em>{ </em>

<em>    return miles * 5280; </em>

<em>} </em>

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

<em>    while(response == 'y') </em>

<em>    { </em>

<em>    cout<<"How many miles did you walk?. "; </em>

<em>    cin>>miles; </em>

<em>    cout<<"You walked "<<convert(miles)<<" feet"<<endl; </em>

<em>    cout<<"Continue? (y/n): "; </em>

<em>    cin>>response; </em>

<em>    } </em>

   cout<<"Bye!";

8 0
3 years ago
If you use your smartphone as a hotspot to connect to the Internet on your tablet you are using a ________.quillet
Nataly [62]
Personal Area Network
7 0
2 years ago
Write a python program to check whether the number is divisible by 7. If its divisible, print its divisible otherwise find previ
Stells [14]

f = int(input("Enter a number: "))

if(f%7==0):

   print("It's divisible by 7.")

else:

   if(f<7):

       print("7")

   else:

       print(str(f-(f%7))+", "+str(f+(7-(f%7))))

7 0
1 year ago
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