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3 years ago

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The current standard for RFID is based off of Group of answer choices MIT standards IEEE standards ISO standards there is no agr

eement on a universal standard that’s accepted by all parties

Computers and Technology

1 answer:

mamaluj [8]3 years ago

4 0

Answer:

ISO standards

Explanation:

ISO / IEC 14443 is the ISO standard that covers RFID usage by devices.

EPCglobal - Electronics Product Code Global Incorporated is also another international standard that covers RFID. These two standards work together to standardize RFID products produced by manufacturers so that these products can be the same across different markets and manufacturers. Example I can purchase a tag from one manufacturer and a transceiver from another and they would function well together. There are also other standards for RFID but the above two are the biggest and most popular with ISO being the oldest.

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Write a function (subroutine) that inputs a data value in register r0 and returns value in r0. The function returns y 5 a 1 bx 1

umka2103 [35]

Solution :

int f(int x){

$\text{return a + b*x +c*x*x}$ ;

}*/

int f( $\text{int R0}$ ){

int stack[2] = { $\text{R1,R2}$ };

$\text{R1 = R0}$ ;

$\text{R1 = R1}\times \text{ R1}$ ;

$\text{R2 = C}$ ;

R1 = R1 * C; /*R1 = $cx^2$ */

$\text{R2 = B}$ ;

$\text{R0 = R0}$ * R2; /* R0 = bx */

$\text{R0 = R0 + R1}$ ; /*R0 = $bx + cx^2$ */

$\text{R2 = C}$ ;

$\text{R0 = R0 + R2}$ ; /*R0 = a+bx+cx^2 */

$\text{R1 = stack[0];}$

$\text{ R2 = stack[1];}$

$\text{ return R0;}$

}

/* $\text{ARM code to implement the following C operation}$

int s=0;

$\text{for ( i = 0; i < 10; i++)}$

{ $\text{s = s + i } \times i$ ;)

*/

AREA SumSquares, code, readWrite

ENTRY

$\text{MOV r0, #0}$ ;loop $\text{ counter i present at 0}$

MOV r1, #0 ; s = 0

Loop $\text{MUL r2, r0, r0}$ ;calculate i*i

$\text{ADD r1, r1, r2}$ ;s = s+ i*i

$\text{ADDS r0, r0}$ , #1 ; i = i+1

$\text{CMP r0}$ ,#10 ; test for end

$\text{BNE}$ Loop ; $\text{continue until all added}$

END

5 0

3 years ago

Keyboards that are widely used on various smartphones and other small portable devices, and which are designed primarily for com

mr Goodwill [35]

Answer:

Option A is the correct answer for the above question.

Explanation:

The keyboard is a device, by which a human can instruct the computer in the text form. There are so many keyboards in which, thumb keyboard is one of them. The thumb keyboard is found in mobile phones, smartphones or PDA phones, which is used for personal use. It is a designed layout of the keyboard that can be placed on the hand of the human and a person can type on its with the help of his thumb.

The above question asked about the type of the keyboard which is used in various smartphones and other phones. That keyboard is thumb keyboard which is described above and it is stated from the option A. So option A is the correct answer while the other is not because--

Option B states about the traditional keyboard which is used for the PC only.
Option C states about the Notebook keyboard which is used for the Notebook computers only.
Option D states about combination which is not a type of keyboard.

7 0

3 years ago

Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.

Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is $\mathbf{2^{20}}$ entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

32-bit logical address
Page size = 4 KB = $\mathbf{2^{12} \ bytes }$
Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = $\mathbf{2^{26} \ bytes}$

Thus, the number of bits in the physical address is computed as:

= $\mathbf{log_2 \{Physical-memory-size\}}$

$=\mathbf{log_2(2^{26})}}$

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table $\mathbf{= \dfrac{2^{32}}{2^{12}}}$

$\mathbf{=2^{20}}$ entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= $\mathbf{2^{20}\times 4 \ bytes}$

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is $\mathbf{2^{20}}$ entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

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1 year ago

Its Simple To delete Your Own Online Poste Or Photos But

tensa zangetsu [6.8K]

its not simple nothing never is deleted from online posts or photos

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3 years ago

Read 2 more answers

How do u create a blank line between two lines in a document

Free_Kalibri [48]

Answer: Press enter at the end of the line.

Explanation:

If you press enter at the end of the line or sentence, it will start a new space underneath your line or sentence.

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3 years ago