Ask question

Ask question

All categories

3 years ago

12

Visitors to the schools website can follow a link to tje schools chorale pictures. If the website had 250 visitors in one week a

nd 3/10 of them visited the chorale pictured, how many visited the chorale pictures?

1 answer:

Nataly_w [17]3 years ago

3 0

It will be 143 views hope this help

You might be interested in

Please help me solve for x =

Sladkaya [172]

Answer:

x = 13

Step-by-step explanation:

Given that Δ NML and Δ PST are similar right triangles, we can set up the following proportional statement to establish their relationship:

$\frac{ML}{NM} = \frac{ST}{PS}$

$\frac{8}{10} = \frac{x - 1}{x + 2}$

Cross multiply:

8(x + 2) = 10 (x - 1)

8x + 16 = 10x - 10

Subtract 8x from both sides:

8x - 8x + 16 = 10x - 8x - 10

16 = 2x - 10

Add 10 to both sides:

16 + 10 = 2x - 10 + 10

26 = 2x

Divide both sides by 2:

$\frac{26}{2} = \frac{2x}{2}$

13 = x

Verify whether x = 13 is the correct value:

$\frac{ML}{NM} = \frac{ST}{PS}$

$\frac{8}{10} = \frac{x - 1}{x + 2}$

$\frac{8/2}{10/2} = \frac{4}{5}$

$\frac{x -1}{x+2} = \frac{13 - 1}{13 + 2} = \frac{12}{15} = \frac{12 / 3}{15 /3} = \frac{4}{5}$

This shows the proportional relationship between $\frac{ML}{NM} = \frac{ST}{PS}$ , and that ΔNML and ΔPST are indeed similar right triangles.

Therefore, the correct answer is x = 13.

4 0

3 years ago

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

3 years ago

georgina works on the 30th floor of a office building she took the elevator to the cafeteria on the 7th floor how many floors di

dezoksy [38]

She traveled 23 floors, 30-7=23.

3 0

3 years ago

Read 2 more answers

PLS HELP GIVE BRAINLIEST

zalisa [80]

Answer:

B 1.8

Step-by-step explanation:

3 0

2 years ago

Based on a poll, 60% of adults believe in reincarnation. Assume that 5 adults are randomly selected, and find the indicated p

vlabodo [156]

Answer:

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they believe in reincarnation, or they do not believe. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 5 adults, so $n = 5$

60% believe in reincarnation, so $p = 0.6$

What is the probability that exactly 4 of the selected adults believe in reincarnation?

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

3 0

3 years ago