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Lorico [155]
3 years ago
11

What is 5+5 guys i need help

Mathematics
2 answers:
ollegr [7]3 years ago
8 0
It is 10, put out your hands you have five fingers each hand, put them together count your fingers you would get 10...
ExtremeBDS [4]3 years ago
7 0
The answer is 10 If you count
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What is 67 16/34 + 14/28 =?​
kirill [66]

Answer:

67.9705...

Add the two numbers.

67 16/34 + 14/28 = 67.9605...

That is your answer.

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! URGENT !!!!! (40 points!!!)
dybincka [34]

Answer:

2

Step-by-step explanation:

the answer is number 2 dm me for more info

8 0
3 years ago
Please help!!<br>i dont know how to do any of this and i really need it done!! ​
Fiesta28 [93]

Answer:

you have to do length times width times height then divide by 2 :)

Step-by-step explanation:

6 0
3 years ago
A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na
Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

v=\frac{d}{t}

where d is the total distance traveled and t is the total time needed.

d=\frac{4.00}{1.75}=2.29 km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0
3 years ago
Which represents the solution set of 5(x+5)&lt;85
boyakko [2]
Divide both sides by 5 , so 5(x + 5)/5 < 85/5  , which will give you <span>x + 5 < 17 , then minus 5 from both sides which will give you x < 12 . hope this helps !</span>
8 0
3 years ago
Read 2 more answers
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