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finlep [7]
3 years ago
8

2 ( 3 x 4) - 10 + 14/2 = 21 true or false

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer:

true

Step-by-step explanation:

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Answer will give brainliest
Lemur [1.5K]

Answer:

1.-202

2.4i-1

3. 195-65i

Step-by-step explanation:

4 0
3 years ago
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Answer choices:<br><br> X=23<br><br> X=63<br><br> X=90
Law Incorporation [45]

Answer:

x = 63

Step-by-step explanation:

x + 2 + 25 = 90

x + 27 = 90

x = 63

I hope that helps.

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2 years ago
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Which inequality corresponds to the sentence "five less than the product of a number and 6 is at least 8"?
Roman55 [17]

Answer:

6x - 5 ≥ 8

Step-by-step explanation:

Which inequality corresponds to the sentence "five less than the product of a number and 6 is at least 8"?

The inequality sign of

a) At least = greater than or equal to = ≥

Let us represent the number as = x

Hence: "five less than the product of a number and 6 is at least 8" can be written as:

= x × 6 - 5 ≥ 8

= 6x - 5 ≥ 8

5 0
2 years ago
4(x - 2) = -12, x = 4​
rewona [7]

Answer:

x= -1

-1 =4

Step-by-step explanation:

3 0
2 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
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