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Pavlova-9 [17]
4 years ago
7

Evaluate the following expression. 3^-2

Mathematics
2 answers:
Crazy boy [7]4 years ago
8 0

Answer: The simplified form is \frac{1}{9}

Step-by-step explanation:

Since we have given that

3^{-2}

As we know the  "Exponential law":

a^{-1}=\frac{1}{a^m}

So, it becomes

3^{-2}=\frac{1}{3^2}

Now, at last it becomes,

3^{-2}=\frac{1}{3\times 3}=\frac{1}{9}

Hence, the simplified form is \frac{1}{9}

Leona [35]4 years ago
6 0
3^ -2 = 1/3^2=1/9. in general a^-x = 1/a^x
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Read 2 more answers
Q6:- Solve 1 ≤ |x –2 | ≤ 3.​
alexandr402 [8]

Answer:

-1<=x<=1 or 3<=x<=5

Step-by-step explanation:

6 0
4 years ago
The answer ISN’T -9/5,3.
Volgvan
<h3>Answer:  [-1.8, 3]</h3>

Don't forget the square brackets.

=============================================

Work Shown:

|5x-3| \le 12\\\\-12 \le 5x-3 \le 12\\\\-12+3 \le 5x-3+3 \le 12+3 \ \text{ ... see note 1}\\\\-9 \le 5x \le 15\\\\-9\div 5 \le 5x\div 5 \le 15\div 5 \ \text{ ... see note 2}\\\\-1.8 \le x \le 3\\\\

note 1: I added 3 to all sides to undo the "-3" in the middle.

note 2: I divided all sides by 5 to go from 5x to x (ie it undoes the multiplication on x).

--------------------

From there, we convert from compound inequality notation to interval notation.

Something in the form a \le x \le b converts to the interval notation [a,b]

The square brackets say to include the endpoint.

So -1.8 \le x \le 3 converts to the final answer of [-1.8, 3]

x is any real number between -1.8 and 3, including both endpoints.

----------------------

It appears you had the right idea. You just needed to convert -9/5 to -1.8, and you also needed to surround everything with square brackets.

If your teacher wanted the answer in fraction form, then you would say [-9/5, 3]

6 0
3 years ago
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