3 years ago

How do you get 8(c-9)=6(2c-12)-4c

1 answer:

6 0

So first you factor it out:

8c - 72 = 12c - 72 - 4c

Then you isolate the c's:

-72 +72 = 12c - 4c -8c

Then you add both sides:

0 = 0c

C is equal to 0

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