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const2013 [10]
3 years ago
9

A right triangle has legs measuring 16 inches and 20 inches what is the length of the hypotenuse

Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

The length of the hypotenuse is 4\sqrt{41}\ in

Step-by-step explanation:

we know that

In a right triangle

Applying the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

c is the hypotenuse

a,b are the legs of the right triangle

substitute the values

c^{2}=16^{2}+20^{2}

c^{2}=256+400

c^{2}=656

c=\sqrt{656}\ in

Simplify

c=4\sqrt{41}\ in

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The shelf is 4 feet wide and 2/3 feet deep. what is the area of the shelf?
steposvetlana [31]

Answer:

Area of the self will be =4\times \frac{2}{3}=\frac{8}{3}=2.666ft^2

Step-by-step explanation:

We have given that self is 4 feet wide and \frac{2}{3} feet deep

So length pf the shelf l = \frac{2}{3} feet

And width = 4 feet

We have to find the area of the self

We know that area is given by

Area = length × width

So area of the self will be =4\times \frac{2}{3}=\frac{8}{3}=2.666ft^2

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3 years ago
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Svetach [21]

Answer:

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Step-by-step explanation:

1) Parallel lines have the same slopes. Write it in standard form (y = mx + c), then substitute the values of the coordinates into the equation.

y = 2/3x + c

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Therefore, the slope-intercept form for the first part is y = 2/3x - 2.

2) Parallel lines have the same slopes. Write it in standard form (y = mx + c), then substitute the values of the coordinates into the equation.

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Therefore, the slope-intercept form for the second part is y = -1/2x + 3.

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yKpoI14uk [10]

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Step-by-step explanation:

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