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taurus [48]
3 years ago
10

9. If 3x = 13 and 2y = 7, what is the value of 3(2x)−2(3y)

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Your're Answer is:

6x - 6y

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zloy xaker [14]
B. You don’t exactly need a reason do you?
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3 years ago
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Triangle ABC has vertices A(5, 3) , B(3, 7) , and C(1, 4) . Triangle ABC is dilated, and the vertices of the image are A′(7.5, 4
Oksana_A [137]
Hello,

To find the scale factor, we have to look at what's going on in the problem. 

In point A, we are converting from (5, 3) to (7.5, 4.5).

We can write and solve equation to find the change (scale factor)

5x = 7.5  and 3x = 4.5

If you solve either equation, you will find the scale factor is 1.5.

Good luck,
MrEQ
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What is the measure for the following ∠?<br> m∠BOA<br><br> 20<br> 40<br> 60
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The answer to your question is 40

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Match the y-coordinate with the given x-coordinate for the equation y = log10x.
Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:


For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.


We know that the equations is:


y=log(10x)


So let's solve each case:


Case 1


x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}


Case 2


x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}


Case 3


x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}


Case 4


x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}


Case 5


x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}

5 0
3 years ago
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11 is less than a number is more greater than 17 
laila [671]

Answer:

This doesnt make, so re write the problem

Step-by-step explanation:

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