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3 years ago

The diagram shows a circle inside a square. work out the area of the circle

Mathematics

1 answer:

Alona [7]3 years ago

7 0

Answer:

i don't know the answer as you haven't given the diagram

Step-by-step explanation:

asumming the circle is touching the square the length of the sides of the square is the diameter of the circle using this information you use the formula area= pie*radius squared find the area.

(radius=half the diameter0

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Plz plz help i have till 11 50 plzplz plz helpppp

OLga [1]

Answer:

i do only 1 part

hope my answer is helpful to you

5 0

3 years ago

Help me please with my math

motikmotik

Answer:

P = 47.1 units

Step-by-step explanation:

the perimeter of the pair of straight opposite sides is 11+11, or 22

now you have 2 semi-circles, which equals 1 full circle which, if we find the circumference to then we just add it to 22 to get the entire answer

Circumference of circle with diameter of 8:

C = 2πr

C = 2π(4)

C = 8π

C = 25.13

now add 22 + 25.13 to get 47.1 rounded to nearest tenths place

5 0

2 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago

What is the unknown term.<br>in the seqpence 4.5, 5.4,____7.2<br><br>A.6.2 or B. 63

harina [27]

Answer:

6.3

Explanation:

To get from 4.5 to 5.4, you need to add 0.9. If you add 0.9 two more times, you get 7.2. Therefore, the middle term should be 6.3. I don't know if you made a typo and forgot the decimal when writing the options cause it says "63", but I believe the answer is 6.3.

4 0

3 years ago

QUICKEST ANSWER GETS BRAINLIEST If you work more than 40 hours a week, then you are paid time and a half (1.5) for all hours ove

Murljashka [212]

Answer:

I think its D 425.50

Step-by-step explanation:

If you do 46 times 9.25 it should be the answer

3 0

3 years ago