Given a quadratic equation
![x^{2} +ax+c=0](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2Bax%2Bc%3D0)
1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +
![5^{2}](https://tex.z-dn.net/?f=%205%5E%7B2%7D%20)
and -
![5^{2}](https://tex.z-dn.net/?f=%205%5E%7B2%7D%20)
to the expression:
![x^{2} +2*5*x+ 5^{2} -5^{2}+9=0](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B2%2A5%2Ax%2B%205%5E%7B2%7D%20-5%5E%7B2%7D%2B9%3D0)
![(x^{2} +2*5*x+ 5^{2}) -25+9=0](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B2%2A5%2Ax%2B%205%5E%7B2%7D%29%20-25%2B9%3D0)
![(x+5)^{2}-16=0](https://tex.z-dn.net/?f=%20%28x%2B5%29%5E%7B2%7D-16%3D0%20)
Answer:
Answer:
<h2>18mins</h2>
Step-by-step explanation:
This problem is on combined work rate
given that
Marta can vacuum the house in 30 min
then her rate= 1/30
Also, her daughter will take 45 min to vacuum the house
her daughter's rate will be = 1/45
then the combined work rate is
1/30+1/45=1/T
30+45/30*45=1/T
75/1350= 1/T
1/18=1/T
This means that they will both take 18 minutes working together to vacum a house
THis would be 62 / 0.56 = 110.71 to nearest hundredth
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