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egoroff_w [7]
3 years ago
5

If function g is defined by the equation y − 3x = -14, which equation represents the function in function notation?

Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

f(x) = 3x - 14

Step-by-step explanation:

note that y = f(x), thus rearrange the equation making y the subject.

Given

y - 3x = - 14 ( add 3x to both sides )

y = 3x - 14 , that is

f(x) = 3x - 14 ← in functional notation

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Factor
solmaris [256]

The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)

We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.

a^2 - b^2 = (a - b)(a + b)

In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.

a^2 = 25m^100 -----> take the square root of both sides

a = 5m^50

Then we can do the same for the b term.

b^2 = 121n^16 ----->take the square root of both sides

b = 11n^8

Now we can use both in the equation already given

(a - b)(a + b)

(5m^50 - 11n^16)(5m^50 + 11n^16)

8 0
3 years ago
Sanjay picked p peaches. Zach picked 17 times as many peaches as Sanjay. Write an expression that shows how many peaches Zach pi
oksano4ka [1.4K]

Answer:

17p

Step-by-step explanation:

Since you don't know how much Sanjay picked you can only explain as a variable. So just put 17 next to p which is 17*p

5 0
3 years ago
Hannah ran 200 feet during recess. Juanita ran 350 feet during recess. In yards, how much further did Juanita run than Hannah?
ss7ja [257]

Juanita ran 240 feet than Hannah

8 0
3 years ago
With the drain open, a pool loses water at a rate of 9 gallons per minute. At that rate, how long will it take to drain 486 gall
Snezhnost [94]

divide 486 by 9 = 54

it would take about 54 minutes

8 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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