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Umnica [9.8K]
3 years ago
12

How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!

Mathematics
1 answer:
Alchen [17]3 years ago
7 0
6x^2 -x-12=0\\
6x^2+8x-9x-12=0\\
2x(3x+4)-3(3x+4)=0\\
(2x-3)(3x+4)=0\\
x=\frac{3}{2} \vee x=-\frac{4}{3}

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5x+4y = -14<br> 3x+6y=6<br> What is the answer
iren [92.7K]

Hallo! Her er svaret ditt på dette spørsmålet! ☺

Answer: If you are solving by Substitution, your answer will be...

Point form : (-6,4)

Equation form : x=-6 , y=4

Step-by-step explanation: Solve for the first variable in one of the euations, then substitute the result into the other equation.

Hope this helps you out! ☺

4 0
3 years ago
The function g is defined as follows.
Radda [10]

Answer:

h(x) =  2x²+2

Step-by-step explanation:

Given the function g is defined as follows.

g(x) = 2x²+7

If the graph is translated by 5units vertically downwards, this means that the function will be reduced by 5 units to have;

h(x) =  2x²+7 - 5

h(x) =  2x²+2

3 0
3 years ago
Help please I’ll give extra points
nirvana33 [79]

Answer:

True!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jacks living room is 16 feet by 20 feet long. if a scale drawing of his living room uses a scale of 3/4 inches= 6 feet, find the
Juli2301 [7.4K]

Answer:

40 inches

Step-by-step explanation:

16×20=320

320÷6=53.33

53.33×3=159.99

159.99÷4=39.9975

39.9975 rounded would be 40

6 0
2 years ago
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

6 0
3 years ago
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