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Umnica [9.8K]
3 years ago
12

How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!

Mathematics
1 answer:
Alchen [17]3 years ago
7 0
6x^2 -x-12=0\\
6x^2+8x-9x-12=0\\
2x(3x+4)-3(3x+4)=0\\
(2x-3)(3x+4)=0\\
x=\frac{3}{2} \vee x=-\frac{4}{3}

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PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!
Tom [10]

Answer:

You have to divide the total sales by 8 percent. 32,000/ 0.8 =40,000

So your answer is 40,000.

Step-by-step explanation:

4 0
3 years ago
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90. The number of daily evening newspapers in the United States has decreased by 46.5% to
aleksandr82 [10.1K]

Answer:

700

Step-by-step explanation:

Given:

Daily evening newspapers in 2015 = 389

Percentage decrease from 2000 to 2015 = 46.5%

To find:

Number of newspapers in 2000 = ?

Solution:

Let the number of newspapers in 2000 = x

When 46.5% of the total newspapers in 2000 (x) is subtracted from the total  newspapers in 2000 (x), it will be equal to the number of newspapers in 2015.

Making the equation as per the given statement:

x-x\times 46.5\%=389\\\Rightarrow \dfrac{100x-46.5x}{100}=389\\\Rightarrow 53.5x=38900\\\Rightarrow x\approx \bold{727}

Therefore, the answer is:

There were <em>727 </em>newspapers in 2000.

7 0
3 years ago
Find the slope of the line.
ira [324]
There it is i found it :)

7 0
3 years ago
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True or false a function can not have a repeat values in the range
SVETLANKA909090 [29]

Answer:

False. false false false false

5 0
3 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
3 years ago
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