How do I solve: 6x^2 -x-12=0 ^2 means squared by the way!

1 answer:

7 0

$6x^2 -x-12=0\\
6x^2+8x-9x-12=0\\
2x(3x+4)-3(3x+4)=0\\
(2x-3)(3x+4)=0\\
x=\frac{3}{2} \vee x=-\frac{4}{3}
$

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