All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer:
The answer is 2.
2 since 6/4=3/2
Step-by-step explanation:
Since your relation is a direct variation then the points on your line are of the form y=kx where k is the constant of variation (also called constant of proportionality)
If y=kx then y/x=k.
So all the points in this relation since it is a direct variation will be equal to y-coordinate/x-coordinate.
So we are going to solve this proportion:

Again I put y/x from each point. They should have same ratio because this is a direct variation.
Cross multiply:


Divide boht sides by 6:


Answer:
f(2) = -2
Step-by-step explanation:
f(2) = 2x - 6
f(2) = 2(2) - 6
f(2) = 4 - 6
f(2) = -2