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3 years ago

Solve the following system pf equations

Mathematics

1 answer:

mr Goodwill [35]3 years ago

5 0

Answer:

Step-by-step explanation:

If you need to do this by graphing, you need to change the format of each equation into slope intersect form

start with 3x-2y=-24

-2y=-3x-24

y=-3/2x+12

To graph this, the y intersect (where it crosses the y axis) is 12 and from there the slope is -3/2

For the next equation,

-3x-y=6

-y=3x+6

y=-3x-6

So the y intersect is -6 and the slope is -3.

Once you graph both of these, the point where both lines cross AKA the intersecion is the solution to the problem.

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Mississippi has the lowest median income at 40.6 thousand dollars. Mississippi also has about 207 bachelor’s degrees per 1,000 p

horsena [70]

Answer:

178

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Algebra 1: Factoring Polynomials Factor the common factor out of each expression: 40n^4m^2+40n^3m^3-32n^3

Nina [5.8K]

Taking out the greatest common factor

GCF of 40, 40 and 32 = 8
GCF of n^4, n^3 and n^3 is n^3

so the factors are

8n^3(5nm^2 +5m^3 - 4)

7 0

3 years ago

Using Unit Rates to compare Ratios continued

nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball $75$ times for $550$ yards, and Pete has $42$ carries for $380$ yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon $=550\text{yards}$

No. of times ball carried by Brandon $=75\text{ times}$

Average yards per carry for Brandon $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{550}{75}$

$=\frac{22}{3}\text{ yards per carry}$

$=7.33\text{ yards per carry}$

Total yards traveled by Pete $=380\text{ yards}$

No. of times ball carried by Pete $=42\text{ times}$

Average yards per carry for Pete $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{380}{42}$

≅ $9\text{ yards per carry}$

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0

3 years ago

Dr. Newton is saving up to buy a car. She has already saved $3,000. If she wants to spend

Nuetrik [128]

Dr. Newton needs 5000 dollars, and 3000 dollars have already been saved. So, 2000 dollars remain.

If these 2000 dollars must be saved withint 8 months, we can divide the amount needed by the time given, to find out that Dr Newton needs to save

$\dfrac{2000}{8}=250$

dollars each month.

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3 years ago

-10(n+30)=1/2(24-14n)

Pavel [41]

N = -104 is the correct answer

6 0

3 years ago