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Mrrafil [7]
3 years ago
5

What is the complex conjugate of 13-21i?

Mathematics
2 answers:
jekas [21]3 years ago
4 0
The conjugate of "anything" is pretty much the same binomial, with a different sign.

ducks + geese     conjugate ->  ducks - geese

cheese - spaghetti     conjugate -> cheese + spaghetti

and so on and so forth.

well, for this one, yeap, you guessed it

 13 - 21i     conjugate -> 13 + 21i.
irga5000 [103]3 years ago
3 0

Answer:

To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.

As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.

Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.

Hope this helped!!... :D

Please correct me if I'm wrong!!.. :3

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Let the number of contestants is n and the prizes is r
the number of ways is npr = 335p3 = 37259370 ways

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3 years ago
Drag a figure into each blank space so that the two figures in the row match the description.
LUCKY_DIMON [66]
What’s the description?
7 0
3 years ago
The price of a house is originally listed at $205,000. The owners are having a hard time selling it and decide to reduce the pri
VARVARA [1.3K]

Answer:

The percentage decrease is 27%

Step-by-step explanation:

To find the percent decrease, first find the difference in the two costs.

$205,000 - $149,650 = $55,350

Now divide that number by the original cost.

$55,350/$205,000 = 27%

3 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has
Neko [114]

Given:

The dimensions:

Square pyramid

Square base: 2x2

1 out of 4 triangles: 1/2x2x5

4 triangles: 2x2x5

To find:

The SURFACE AREA of the square pyramid

Find answer:

Step 1

Find the area of the square base -

Square base:

SA = L x W

= 2 x 2

= 4

<em>The surface area of the square is 4 square inches</em>

<em></em>

Step 2

Find the area of the 4 Triangles:

We will use a different formula here, to find 1 triangle, we will have to do:

SA = \frac{1}{2} *B*H

To find 2 triangles, we will do:

SA = B*H

But to find 4 triangles in just 1 step, we will do:

SA=2*B*H

Let's do it!

SA = 2*2*5\\=2*10\\=20

<em>The surface area of the 4 triangles are 20 square inches</em>

<em></em>

Step 3

Add answers to get FINAL ANSWER

Easy!

20+4=24

<h2>Hence, the Surface Area of the Square Pyramid is 24 square inches</h2>

<em></em>

<em></em>

4 0
2 years ago
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