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Answer:
The area of circle with radius half of original circle is 7 π cm² .
Step-by-step explanation:
Given as :
The Area of original circle = 28 π square centimeter
Let The radius of original circle = R
Let The area of circle with radius half of original circle = A square centimeters
Let The radius of circle with radius half of original circle = R'
Now, According to question
∵ Area of original circle = π × radius²
So, 28 π cm² = π × R²
Or, R² =
Or, R² = 28 cm²
∴ R = cm
i.e R = 2 cm
So, The radius of original circle = R = 2 cm
<u>Again</u>
∵ The radius of circle with radius half of original circle = R'
So, R' =
i.e R' =
∴ R' = cm
So, The area of circle with radius half of original circle = π × R'²
i.e A = π × R'²
Or, A = π ×() ²
or, A = π × 7
So, The area of circle with radius half of original circle = 7 π cm²
Hence The area of circle with radius half of original circle is 7 π cm² . Answer