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3 years ago

Suzie earns 27000 a year what is her weekly pay

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

Answer: Suzie's weekly pay is: $519.23 .

<u>Step-by-step explanation</u>:

$ 27,000 / yr. = ? dollars / week.

__________________________________________________

Assume: " 1 yr = 52 wk(s.) " ;

$\frac{27,000 dollars}{yr}$ * $\frac{1 yr}{52 wks}$ ;

= $\frac{(27,000 dollars * 1) }{52 wk}$ ;

= $\frac{27,000 dollars}{52 wk}$ ;

= $\frac{27,000}{52}$ dollars per week ;

= {27,000 ÷ 52) dollars per week ;

= { 519.230769231 ) dollar per week ;

= $519.23 / wk.

Answer: Suzie's weekly pay is: $519.23 .

__________________________________________________

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2 years ago

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2 years ago

Find the endpoint:

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Answer:

The coordinates of Point D are: (-5,-8)

Step-by-step explanation:

The formula for mid-point is given by:

$M = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})$

For the point (x1,y1) and (x2,y2)

Given that

M = (-3, -6)

C = (-1, -4) => (x1,y1)

Putting the values of given points in the formula for mid-point

$(-3,-6) = (\frac{-1+x_2}{2} , \frac{-4+y_2}{2})$

Putting respective coordinates equal

$-3 = \frac{-1+x_2}{2}\\-6 =-1+x_2\\x_2=-6+1\\x_2 = -5\\AND\\-6 = \frac{-4+y_2}{2}\\-12 = -4+y_2\\y_2 = -12+4\\y_2 = -8$

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2 years ago

Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through

stiks02 [169]

Answer:

$x + 2y= 2$

Step-by-step explanation:

Given

Points:

$F = (4,9)$

$G = (1,3)$

Required

Determine the equation of line that is perpendicular to the given points and that pass through $(2,0)$

First, we need to determine the slope, m of FG

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$F = (4,9)$ --- $(x_1,y_1)$

$G = (1,3)$ --- $(x_2,y_2)$

$m = \frac{3 - 9}{1 - 4}$

$m = \frac{- 6}{- 3}$

$m =2$

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

$m_2 = -\frac{1}{m}$

$m_2 = -\frac{1}{2}$

The equation of the line is then calculated as:

$y - y_1 = m_2(x - x_1)$

Where

$m_2 = -\frac{1}{2}$

$(x_1,y_1) = (2,0)$

$y - 0 = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}x + 1$

Multiply through by 2

$2y = -x + 2$

Add x to both sides

$x + 2y= -x +x+ 2$

$x + 2y= 2$

Hence, the line of the equation is $x + 2y= 2$

8 0

3 years ago

Read 2 more answers