$\bf 7sin^2(x)-14sin(x)+2=-5\implies 7sin^2(x)-14sin(x)+7=0 \\\\\\ \stackrel{\textit{notice, this is just }ax^2+bx+c}{\stackrel{\stackrel{ax^2}{\downarrow }}{sin^2(x)}\stackrel{\stackrel{bx}{\downarrow }}{-2sin(x)}\stackrel{\stackrel{c}{\downarrow }}{+1}}=0\implies [sin(x)-1][sin(x)-1]=0 \\\\\\ sin(x)-1=0\implies sin(x)=1\implies \measuredangle x=sin^{-1}(1)\implies \measuredangle x=\cfrac{\pi }{2} \\\\\\ ~~~~~~~~~~~~~~\stackrel{\textit{and for all solutions using }n \in \mathbb{Z}}{\cfrac{\pi }{2}+2\pi n}$

7 0

4 years ago

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Please help!<br> is there any solutions?

Digiron [165]

The equations will only have one solution because they have different slopes and also next time use desmos for those kinds of problems it’ll always help

5 0

3 years ago

Are these ratios equivalent?<br> 2:4 and 6:16

Grace [21]

Answer:

Step-by-step explanation:

2:4 is 1:2, 6:16 is not one half

4 0

3 years ago

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Select the expression that is equivalent to -4(3m - 5)

spin [16.1K]